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notsponge [240]

4 years ago

5

Half as many pages as george read

1 answer:

Sedbober [7]4 years ago

4 0

I feel like this question might lack something. But I assume that what is being asked in this problem is the expression that would best represent the number of pages that someone, apart from George, has actually read. Let x be the number of pages that George read. The expression for half what George read is x/2.

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Assume that a procedure yields a binomial distribution with n trials and the probability of success for one trial is p. Use the

KiRa [710]

Answer:

395, 17.212

(360.576,429.424)

Step-by-step explanation:

Given that a procedure yields a binomial distribution with n trials and the probability of success for one trial is p.

Here $n=1580and p =1/4 =0.25\\q = 0.75\\np = 395 and\\nq = 1185$

Since np and nq are greater than 5 by rule of thumb we can approximate binomial to normal.

Mean = np = 395

Variance = npq = $395*0.75=296.25$

Std dev = 17.212

Thus X no of successes is N(395, 17.212)

THe the minimum usual value mu minus 2 sigma and the maximum usual value mu plus 2 sigma would be

$395-2(17.212), 395+2(17.212)\\= 360.576,429.424$

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Step-by-step explanation:

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