51 ft I believe if you have the same question as I did..
1-Find an equation of the plane.
The plane that passes through (8,0,-1)
and contains the line x=4-4t , y=1+5t , z=4+2t
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2-Find an equation of the plane.
The plane that passes through the point (-2,2,2)
and contains the line of intersection of the planes
x+y-z=3 and 3x-y+5z=5
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3-Find an equation of the plane.
The plane that passes through the line of intersection of the planes x-z=1 and y+2z=2
and is perpendicular to the plane x+y-4z=3
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4-Where does the line through
<span>(1, 0, 1) and (4,-2,3)intersect the plane</span><span>x + y + z = 8 ?</span>
Answer:
the best way to to do this would be to use a protractor, if you don't have one you would have to guess on the 15 degrees, but it would be a very small angle
Answer:
Step-by-step explanation:
1. Find two numbers that add to make the coefficient of x (in this case, -5) and that multiply to make the constant term multiplied by the coefficient of x^2 (in this case, -2 x 3 = -6)
Two numbers that work are -6 and +1
-6 x +1 = -6
-6 + -1 = -5
2. Split the middle term into the two numbers that you found.
3x^2 -6x +x -2 = 0
I've put the -6 on the left side because in our next step, when we factorise, it will be easier than having the numbers the other way around.
3. Factorise the left side by taking out common factors from each pair. The pairs I'm talking about here are '3x^2 and -6x', and 'x and -2'
3x (x-2) +1 (x-2) = 0
4. You now have two numbers both being multiplied by the term x-2. We can rearrange this equation to give us two brackets being multiplied by each other.
(3x + 1) (x-2) = 0
5. According to the Null Factor Law, if two terms are multiplied together and the result is 0, then one of those terms must be 0. Make both terms equal to 0 and solve each for x.
3x + 1 = 0 x-2 = 0
3x = -1 x = 2
x = -1/3
6. The solutions to this equation are x = 2 and x = -1/3
