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3 years ago

At the farmer’s market, you can buy 3 melons for $13.50. What is the cost of one melon

Mathematics

1 answer:

Virty [35]3 years ago

7 0

Answer:

4.50 per melon

Step-by-step explanation:

Take the price and divide by the number of melons

13.50/3

4.50 per melon

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Oak pollen sent 21,000 people to U.S. emergency rooms for asthma in 2010. By 2090 the rate could climb another 5 or 10 percent.

Gnesinka [82]

The probable number of prople sent to US emergency rooms by 2090 can be between 22,050 and 23,100

Step-by-step explanation:

Total sent to US emergency room by 2010= 21000

The estimated increase in the rise of cases = 5 to 10% by 2090

Final numbers in 2090

Hence the final numbers in 2090 would be 5 to 10% more than the total cases in 2010

Lower limit= 5% of 21000= 1050

Hence lower limit of cases in 2090= 21000+1050= 22050

Upper limit of cases in 2090= 10% of 21000= 21000+2100= 23,100

The number would lie anywhere between 22050 and 23,100 in 2090

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An SRS of ten brands of breakfast cereals is tested for the number of calories per serving. The following data result: 185, 190,

Pepsi [2]

Using the t-distribution, as we have the standard deviation for the sample, it is found that the 95% confidence interval estimate for the mean number of calories for servings of breakfast cereals is (195.3, 215.7).

<h3>What is a t-distribution confidence interval?</h3>

The confidence interval is:

$\overline{x} \pm t\frac{s}{\sqrt{n}}$

In which:

$\overline{x}$ is the sample mean.
t is the critical value.
n is the sample size.
s is the standard deviation for the sample.

From the sample and the significance level of 0.05, we have that the parameters are given by:

$\overline{x} = 205.5, s = 14.2, n = 10, t = 2.2622$

Hence:

$\overline{x} - t\frac{s}{\sqrt{n}} = 205.5 - 2.2622\frac{14.2}{\sqrt{10}} = 195.3$

$\overline{x} + t\frac{s}{\sqrt{n}} = 205.5 + 2.2622\frac{14.2}{\sqrt{10}} = 215.7$

The 95% confidence interval estimate for the mean number of calories for servings of breakfast cereals is (195.3, 215.7).

More can be learned about the t-distribution at brainly.com/question/16162795

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