Answer:
X^2 + 5x + 6
Step-by-step explanation:
(X times X) + (x times 2) + (x times 3) + ( 3 times 2)
X^2 + (2x) + (3x) + 6
combind like terms
X^2 + 5x + 6
Answer:
Step-by-step explanation:
113= (2x+33)+(3x+20)
113=5x+53
60=5x
X=12
NOT DONE YET
substitute x value into MON equation to find angle measure
you get 57 degrees
Answer:
x = 1
Step-by-step explanation:
3(x + 6) -5 = 16
You want to first add the 5 (*flipping the sign) over to the 16
making your equation ...
3(x +6) = 21
Then you want to distribute the 3 to x and 6
making you equation
3x + 18 = 21
Then you want to subtract the 18 (*flipping the sign) to the right side
making the equation....
3x = 3
Lastly, divide the 3 on the left to the 3 on the right making the answer 1
x = 1
Answer:
a) 4x + 76 = 180 (x = 26)
b)
- m<1 = 102
- m<2 = 78
Step-by-step explanation:
First we know 4x + 76 = 180. The reason for that is we know angle one plus angle two = 180 so 3x + 1x + 76 has to equal 180.
We can solve for x now.
4x + 76 = 180.
Subtract 76 to maintain equality on both sides.
4x = 104.
x = 26
Now we can get the angles.
For angle #1 let's substitute x as 26.
angle one = 26 + 76.
angle one = 102
For angle #2 let's substitute x as 26.
angle two = 3(26)
angle two = 78
Let's check!
78 + 102 = 180.
180 = 180 YES
Well, this took some time :)
Answer:
C
Step-by-step explanation:
Remember that if s(t) is a position function then:
is the velocity function and
is the acceleration function.
So, to find the acceleration, we need to solve for the second derivative of our original function. Our original function is:

So, let's take the first derivative first with respect to t:
![\frac{d}{dt}[s(t)]=\frac{d}{dt}[t^2+4t+10]](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdt%7D%5Bs%28t%29%5D%3D%5Cfrac%7Bd%7D%7Bdt%7D%5Bt%5E2%2B4t%2B10%5D)
Expand on the right:
![s'(t)=\frac{d}{dt}[t^2]+\frac{d}{dt}[4t]+\frac{d}{dt}[10]](https://tex.z-dn.net/?f=s%27%28t%29%3D%5Cfrac%7Bd%7D%7Bdt%7D%5Bt%5E2%5D%2B%5Cfrac%7Bd%7D%7Bdt%7D%5B4t%5D%2B%5Cfrac%7Bd%7D%7Bdt%7D%5B10%5D)
Use the power rule. Remember that the derivative of a constant is 0. So, our derivative is:

This is also our velocity function.
To find acceleration, we want to second derivative. So, let's take the derivative of both sides again:
![\frac{d}{dt}[s'(t)]=\frac{d}{dt}[2t+4]](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdt%7D%5Bs%27%28t%29%5D%3D%5Cfrac%7Bd%7D%7Bdt%7D%5B2t%2B4%5D)
Again, expand the right:
![s''(t)=\frac{d}{dt}[2t]+\frac{d}{dt}[4]](https://tex.z-dn.net/?f=s%27%27%28t%29%3D%5Cfrac%7Bd%7D%7Bdt%7D%5B2t%5D%2B%5Cfrac%7Bd%7D%7Bdt%7D%5B4%5D)
Power rule. This yields:

So, our answer is C.
And we're done!