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inna [77]
4 years ago
7

e=" \sqrt[3]{ \frac{ - 512}{1000} } " alt=" \sqrt[3]{ \frac{ - 512}{1000} } " align="absmiddle" class="latex-formula">
​
Mathematics
2 answers:
pav-90 [236]4 years ago
8 0
-4/5 was the answer I had gotten.
hammer [34]4 years ago
8 0

Answer:

-\frac{4}{5}                       OR       -0.8

Step-by-step explanation:

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Omg please help me im literally dying
Karolina [17]

Answer:

(-2,3)

Step-by-step explanation:

Multiply -3x+4y=18 with 2:

-6x+8y=36

Add -6x+8x=36 and 6x+2y=-6

10y=30

y=3

So y=3 we can replace y with 3 on any of these two equations:

6x+6=-6

Move the 6 to the other side:

6x=-12

x=-2

So the solution is

(-2,3)

Hope this helps

6 0
3 years ago
Pls tell me which square unit :(
Crazy boy [7]

Answer:

8

Step-by-step explanation:

If I am doing this correctly you count all the dots the triangles lines are on. Which is 8 to find the area. Hope it helped have a wonderful day!

8 0
3 years ago
3/2 -3 nananmxmxnxn, knsnnzn
Veseljchak [2.6K]

what? how can i help you

6 0
4 years ago
What is m∠AEB? <br> (See attachment)
aleksley [76]
Hey there,
Angle AEB + Angle CED = 180 degrees (vertically opposite angles)
(5x-10) degrees + (3x + 40) degrees = 180 degrees
5x -10 + 3x + 40 = 180 degrees
5x + 3x= 180 + 10 - 40
8x = 150
x = 150 / 8
   = 18.75 degrees 
Angle AEB = (18.75 x 5) - 10 
                  =83.75 degrees.

Hope this helps ^_^

~Top
3 0
3 years ago
Para embalar una caja se emplea 4,2 m de cinta adhesiva. ?Cuántas cajas se podrán embalar con tres rollos que tienen 3 hm, 7 dam
kompoz [17]

For this case, we perform the conversions:

First roll:

1 \ Hectometer --------> 100 \ meters\\3 \ Hectometer --------> x

x = \frac {3 * 100} {1}\\x = 300 \ meters.

We make a rule of three to determine the number of "c" boxes that can be packed with 300 meters of adhesive tape.

1 -----------> 4.2

c -----------> 300

c = \frac {300 * 1} {4.2}\\c = 71.42857143\\c = 71

You can pack 71 boxes.

Second roll:

1 \ Decametro --------> 10 \ meters\\7 \ Decameter --------> x\\x = \frac {7 * 10} {1}\\x = 70 \ meters.

We make a rule of three to determine the number of "c" boxes that can be packed with 70 meters of adhesive tape.

1 -----------> 4.2

c -----------> 70

c = \frac {70 * 1} {4.2}\\c = 16.66666667\\c = 16

You can pack 16 boxes.

Third roll:

1 -----------> 4.2

c -----------> 50

c = \frac {50 * 1} {4.2}\\c = 11.9047619\\c = 11

You can pack 11 boxes.

Thus, in total you can pack11 + 16 + 71 = 98 \ boxes

Answer:

98 boxes

4 0
4 years ago
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