Question

The hypotenuse of a right angle triangle is x + 6. The other two sides are 12 and x. Form an equation involving x and then solve it.

Answer 1

Answer:

X=9

Solution,

AB=(perpendicular)=X

AC(hypotenuse)=X+6

CB(Base)=13

Using Pythagoras theorem,

${h}^{2} = {p}^{2} + {b}^{2} \\ {(x + 6)}^{2} = {x}^{2} + {(12)}^{2} \\ {x}^{2} + 12x + 36 = {x}^{2} + 144 \\ 12x + 36 = 144 \\ 12x = 144 - 36 \\ 12x = 108 \\ x = \frac{108}{12} \\ x = 9$

Hope this helps...

Good luck on your assignment...

Answer 2

Answer:

The answer is x = 9

We use Pythagoras theorem to form the equation and solve for x

That's

a² = b² + c²

where a is the hypotenuse

we get

(x + 6)² = 12² + x²

Expand

x² + 12x + 36 = 144 + x²

Group like terms

We have

x² - x ² + 12x = 144 - 36

12x = 108

Divide both sides by 9

That's

12x/12 = 108/12

x = 9

Hope this helps you.