Answer:
$15600
Step-by-step explanation:
Minimum number of samples can be calculated using the formula:
N≥
where
- N is the sample size
- z is the corresponding z-score for 95% confidence level (1.96)
- s is the standard deviation of the calorie consumption (450 cal.)
- ME is the margin of error that the researcher is willing to accept. (50 cal)
N≥
=311.2
Therefore, minimum required sample size for 50 cal standard error in 95% confidence is 312
Since the survey costs $50 for each person then the survey costs minimum
50*312=$15600
Answer:
-6
Step-by-step explanation:
we just need to do the step slope=(y2-y1)/(x2-x1)
so slope =-30-(-54)/(7-11)=24/-4=-6
Answer:
c I think but I am not sure but I hope you have a good day
Answer:
9 hours
Step-by-step explanation:
Firstly,
Minus $123.10 with $34
123.10-34
= 89.10
(bcuz $34 is the reservation fee)
Secondly,
Divide $89.10 with $9.90 to determine the hours
t = 89.10/9.90
= 9
Last answer = 9 hours
You will set the equation up as part/whole = percent/100 and when you replace it with your numbers you get 60/x = 80/100 now you cross multiply and do 60*100 = 80 * x and you get 6,000 = 80x now you divide both sides by 80 then you get 75 was the original price
