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Reil [10]
2 years ago
6

the instantaneous growth rate r of a colony of bacteria t hours after the start of an experiment is given by the function r=0.01

t^3-0.07t^2+0.07t+0.15 for 0≤t≤7. find the times for which the instantaneous growth rate is zero.​
Mathematics
1 answer:
mojhsa [17]2 years ago
5 0

Answer:

t = 5,-1,3

Step-by-step explanation:

r=0.01t^3-0.07t^2+0.07t+0.15

For simplification let's multiply the equation by 100

100r = t³ - 7t² + 7t + 15

When r= 0

t³ - 7t² + 7t + 15= 0

Let's look for the value of t.

Let's try a possible division

(t³ - 7t² + 7t + 15)/(t-5) = t² -2t -3

So we've gotten one as t-5

Let's factorize t² -2t -3

= t² +t -3t -3

= t(t+1) -3(t+1)

= (t+1)(t-3)

So we have

(t-5)(t+1)(t-3)

What it means is that the possible values are when

t = 5,-1,3

These are also called the roots of the equation

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X + 3/2 = 3/4 (x - 1/2)
Iteru [2.4K]

this would be your answer, <em>x = 1 - 15/2.</em>

Thanks,

<em>Deku ❤</em>

8 0
3 years ago
Its pretty easy if you are good at math! Please help!
aleksley [76]

Step-by-step explanation:

Explanation:

The trick is to know about the basic idea of sequences and series and also knowing how i cycles.

The powers of i will result in either: i, −1, −i, or 1.

We can regroup i+i2+i3+⋯+i258+i259 into these categories.

We know that i=i5=i9 and so on. The same goes for the other powers of i.

So:

i+i2+i3+⋯+i258+i259

=(i+i5+⋯+i257)+(i2+i6+⋯+i258)+(i3+i7+⋯+i259)+(i4+i8+⋯+i256)

We know that within each of these groups, every term is the same, so we are just counting how much of these are repeating.

=65(i)+65(i2)+65(i3)+64(i4)

From here on out, it's pretty simple. You just evaluate the expression:

=65(i)+65(−1)+65(−i)+64(1)

=65i−65−65i+64

=−65+64

=−1

So,

i+i2+i3+⋯+i258+i259=-1

8 0
3 years ago
The grass in Jamie’s yard grew 16 centimeters in 10 days. Kit was growing at a constant rate how many days did it take the grass
lapo4ka [179]
0.625 day to grow 1 cm.

16/10 = 1.6 cm in day.


I hope that help ✌️
7 0
2 years ago
Please help me with my math im tired<br> (ill give u brainliest)
klasskru [66]

Answer:

below given

Step-by-step explanation:

1) yes

2)no

3)no

4)yes

5)no

7 0
2 years ago
Read 2 more answers
Rounded to the nearest hundred cubic meters, what is the total capacity (cone and cylinder) of the storage container?
hichkok12 [17]
The picture in the attached figure

we know that
the total capacity of the storage container=volume of a cone+volume of cylinder

step 1
find the volume of a cone
volume of a cone=(1/3)*pi*r²*h
r=6 m
h=8 m
so
volume=(1/3)*pi*6²*8-----> 301.44 m³

step 2
find the volume of the cylinder
volume of a cylinder=pi*r²*h
r=6 m
h=10 m
s6
volume=pi*6²*10----> 1130.40 m³

total volume=301.44+1130.4-----> 1431.84 m³-------> 1400 m³

the answer is
1400 m³

5 0
3 years ago
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