Answer:
The magnitude of the electric force between these two objects
will be: 181.274 N.
i.e. F
N
Step-by-step explanation:
As
Two object accumulated a charge of 4.5 μC and another a charge of 2.8 μC.
so
q₁ = 4.5 μC = 4.5 × 10⁻⁶ C
q₂ = 2.8 μC = 2.8 × 10⁻⁶ C
separated distance = d = 2.5 cm
Calculating the magnitude of the force between two charged objects using the formula:


∵ 
∵ 


∵ 
∵ 

F
N
Therefore, the magnitude of the electric force between these two objects will be: 181.274 N.
i.e. F
N
Answer:
2√14
Step-by-step explanation:
√56
√2^2 x 14
√2^2 √14
2√14
Answer:
75.44 Square Inches
Step-by-step explanation:
The diagram of the problem is produced and attached.
To determine the area of the cleaned sector:
Let the radius of the larger sector be R
Let the radius of the smaller sector be r
Area of the larger sector 
Area of the smaller sector 
Area of shaded part =Area of the larger sector-Area of the smaller sector

From the diagram, R=10 Inch, r=10-7=3 Inch, 
Therefore, Area of the sector cleaned

Answer:
B and F
Step-by-step explanation:
Example of integers are -5 ,1 ,5 , 8 , 97 and 3,043