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3 years ago

Jim baked 31 cookies. His family ate m of them. Using m, write an expression for the number of cookies that remained.

Mathematics

2 answers:

kakasveta [241]3 years ago

8 0

Answer:

31 - m

Step-by-step explanation:

Expressions don't have the equal sign, equations do.

Serggg [28]3 years ago

4 0

Answer:

31-m

Step-by-step explanation:

Hope this helps!

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What is the correct reason for statement 1

olya-2409 [2.1K]

Answer:

Given

Step-by-step explanation:

You are given the information about the angles under the line given.

6 0

3 years ago

Sinx=cos19∘ What is the value of x? Enter your answer in the box.

rusak2 [61]

Remember that cos is just a translation of sin and vice versa.
So:
Sin(x) = Cos(90 - x)
Cos(x) = Sin(90 - x)

Therefore, to answer your question:
Cos(19) = Sin(90 - 19)
= Sin(71)

6 0

3 years ago

HELP PLEASEEE

jeka94

The exact circumference of the circle is $7 \frac{49}{150} k m$

The approximate circumference of the circle is $7.33 k m$

Explanation:

The diameter of the circle is $2 \frac{1}{3} \mathrm{km}$

Now, we shall find the circumference of the circle.

The formula to determine the circumference of the circle is given by

$C=\pi d$

Where C is the circumference , $\pi$ is 3.14 and $d=2 \frac{1}{3} \mathrm$ is the diameter of the circle.

The exact circumference of the circle is given by

$\begin{aligned}C &=\pi d \\&=(3.14)\left(2 \frac{1}{3}\right) \\&=(3.14)\left(\frac{7}{3}\right) \\&=\frac{21.98}{3}\end{aligned}$

Multiply both numerator and denominator by 100, we get,

$C=\frac{2198}{300} \\C=\frac{1099}{150}$

Converting $\frac{1099}{150}$ into mixed fraction, we get,

$C=7 \frac{49}{150}$

Thus, the exact circumference of the circle is $7 \frac{49}{150} k m$

The approximate value of the circumference can be determined by dividing the value $\frac{1099}{150}$

$C=\frac{1099}{150}=7.327$

$C=7.33km$

Thus, the approximate circumference of the circle is $7.33 k m$

3 0

4 years ago

Use some of the digits 1,3,5,7,9 only once to write 5 numbers less than 2000

Yuri [45]

Answer:

1357, 1359, 1579, 1573, 1375, 1379, 1957, 1953

Step-by-step explanation:

Since this number needs to be less than 2000, the first number has to be 1. You can randomly pick and choose any of the numbers after that.

3 0

4 years ago

What is the coefficient of the x^5y^5- term in the biomial expansion of (2x-3y)^10

jasenka [17]

Answer:

The coefficient of $x^{5} \times y^{5} \text { is }=\left(252 \times 2^{5} \times(-3)^{5}\right)=252 \times 32 \times 243=1959552$

Solution:

The given expression is $(2 x-3 y)^{10}$

As per binomial theorem, we know,

$(x+y)^{n}=\sum n C_{k} x^{n-k} y^{k}$

Now here a = 2x, b = (- 3y) and n = 10 and k = 0,1,2,….10

Now $x^{5}\times y^5$ will be the 6 term where k =5

Now, $\mathrm{T}_{6}=10 \mathrm{C}_{5} \times(2 \mathrm{x})^{(10-5)} \times(-3 \mathrm{y})^{5}=10 \mathrm{C}_{5} 2^{5} \times \mathrm{x}^{5} \times(-3)^{5} \times \mathrm{y}^{5}$

So, the coefficient of $x^{5} \times y^{5} \text { is }=10\left(5 \times 2^{5} \times(-3)^{5}\right$ .

$10 \mathrm{C}_{5}=\frac{10 !}{5 ! \times(10-5) !}=\frac{10 !}{5 !+5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6 \times 5 !}{5 ! \times 5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6}{5 \times 4 \times 3 \times 2 \times 1}=\left(\frac{30240}{120}\right)=252$

The coefficient of $x^{5} \times y^{5} \text { is }=\left(252 \times 2^{5} \times(-3)^{5}\right)=252 \times 32 \times 243=1959552$

6 0

3 years ago