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xxTIMURxx [149]
4 years ago
13

What is the sum?

exFormula1" title=" \frac{3}{x^-9} + \frac{5}{x+3} " alt=" \frac{3}{x^-9} + \frac{5}{x+3} " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
olchik [2.2K]4 years ago
4 0
Make denomenators the same

times left denomenator by (x+3)/(x+3) and right one by (x-9)/(x-9)

\frac{3(x+3)}{(x-9)(x+3)}+  \frac{5(x-9)}{(x-9)(x+3)}=
\frac{3(x+3)+5(x-9)}{(x-9)(x+3)}=
\frac{3x+9+5x-45}{(x-9)(x+3)}=
\frac{8x-36}{(x-9)(x+3)}

if expandded we get
\frac{8x-36}{x^2-6x-27}
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Step-by-step explanation:

he area of circle A is three times the area of circle B.

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