Answer:
First question: LCL = 522, UCL = 1000.5
Second question: A sample size no smaller than 418 is needed.
Step-by-step explanation:
First question:
Lower bound:
0.36 of 1450. So
0.36*1450 = 522
Upper bound:
0.69 of 1450. So
0.69*1450 = 1000.5
LCL = 522, UCL = 1000.5
Second question:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
The margin of error is:

The project manager believes that p will turn out to be approximately 0.11.
This means that 
95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The project manager wants to estimate the proportion to within 0.03
This means that the sample size needed is given by n, and n is found when M = 0.03. So






Rounding up
A sample size no smaller than 418 is needed.
this is the easiest question ever what the fk
Answer: 0.42 and 5 outcomes.
Step-by-step explanation:
i guess that carlos has a fair coin and a number cube.
the probability can be calculated as the number of outcomes that we want divided the total number of outcomes.
The coin has two possible outcomes, heads and tails, then the probability of getting heads is p1 =1/2
the number cube has 6 numbers, 5 of those 6 numbers are greater than 1, then the probability of getting a number greater than 1 is p2 =5/6
the joint probability is the product of those two:
P = 1/2*5/6 = 5/12 = 0.42
The combinations that include heads and number greater than 1 are 5 combinations:
Heads and 2
Heads and 3
Heads and 4
Heads and 5
Heads and 6.
Answer:
i think option d tan theta =0
Answer: Bridge is 21 years old
Step-by-step explanation:
Ok so after reading the question I already know that B (Bridget), A (Angad) and P (Paul) is 49 in the sum of age. I also know that B=A+5 and P=A-4. After that I can assume B=P+5+4. So now after we gather everything, the age of all of them is the same if we delete 5, 4, 4 (From B=P+5+4 and P=A-4). 49-5-4-4=36. So now lets assume they are all 12 (36/3=12). B is 5 years older so lets add 5 to B. B=17, A=12 and P=8. 8+12+17= 37. We now know that but 37 is 12 under 49, so lets add the average 12/3=4 so we add 4 to all of them. B=21 A=16 P=12. 21+16+12=49. So Bridge is 21 years old, Angad is 16 years old and Paul is 12 years old