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Katena32 [7]
3 years ago
12

Find the area of the regular polygon below and round your answer to the nearest tenth.

Mathematics
1 answer:
stira [4]3 years ago
4 0
The 9-sided polygon will have a central angle between the vertex and the center of one side of 360°/(2*9) = 20°. Then the apothem is
  a = (6 in/2)*cot(20°) ≈ 8.242432 in
The perimeter is 9*6 in = 54 in, so the area is
  A = (1/2)Pa = (1/2)*(54 in)*(8.242432 in) ≈ 222.5 in²
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Two sisters, sister A and sister B, play SCRABBLE with each other every evening. Sister A is a statistician, and she draws a ran
snow_tiger [21]

Answer:

First question: LCL = 522, UCL = 1000.5

Second question: A sample size no smaller than 418 is needed.

Step-by-step explanation:

First question:

Lower bound:

0.36 of 1450. So

0.36*1450 = 522

Upper bound:

0.69 of 1450. So

0.69*1450 = 1000.5

LCL = 522, UCL = 1000.5

Second question:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

The project manager believes that p will turn out to be approximately 0.11.

This means that \pi = 0.11

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The project manager wants to estimate the proportion to within 0.03

This means that the sample size needed is given by n, and n is found when M = 0.03. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.96\sqrt{\frac{0.11*0.89}{n}}

0.03\sqrt{n} = 1.96\sqrt{0.11*0.89}

\sqrt{n} = \frac{1.96\sqrt{0.11*0.89}}{0.03}

(\sqrt{n})^2 = (\frac{1.96\sqrt{0.11*0.89}}{0.03})^2

n = 417.9

Rounding up

A sample size no smaller than 418 is needed.

6 0
3 years ago
Which of these inequalities is correct
Ilia_Sergeevich [38]

this is the easiest question ever what the fk

4 0
3 years ago
Carlos has a fair die and a number cube. He will flip the fair die one time and roll the number cube one time. What is the proba
saul85 [17]

Answer: 0.42 and 5 outcomes.

Step-by-step explanation:

i guess that carlos has a fair coin and a number cube.

the probability can be calculated as the number of outcomes that we want divided the total number of outcomes.

The coin has two possible outcomes, heads and tails, then the probability of getting heads is p1 =1/2

the number cube has 6 numbers, 5 of those 6 numbers are greater than 1, then the probability of getting a number greater than 1 is p2 =5/6

the joint probability is the product of those two:

P = 1/2*5/6 = 5/12 = 0.42

The combinations that include heads and number greater than 1 are 5 combinations:

Heads and 2

Heads and 3

Heads and 4

Heads and 5

Heads and 6.

5 0
3 years ago
1!<br><br><br><br><br> please help!!<br><br><br> math geniuses where r uuuu<br><br><br><br> help!
Serhud [2]

Answer:

i think option d tan theta =0

3 0
2 years ago
Bridget is 5 years older than Angad. Paul is 4 years younger than Angad. If the total of their
Ainat [17]

Answer: Bridge is 21 years old

Step-by-step explanation:

Ok so after reading the question I already know that B (Bridget), A (Angad) and P (Paul) is 49 in the sum of age. I also know that B=A+5 and P=A-4. After that I can assume B=P+5+4. So now after we gather everything, the age of all of them is the same if we delete 5, 4, 4 (From B=P+5+4 and P=A-4). 49-5-4-4=36. So now lets assume they are all 12 (36/3=12). B is 5 years older so lets add 5 to B. B=17, A=12 and P=8. 8+12+17= 37. We now know that but 37 is 12 under 49, so lets add the average 12/3=4 so we add 4 to all of them. B=21 A=16 P=12. 21+16+12=49. So Bridge is 21 years old, Angad is 16 years old and Paul is 12 years old

5 0
3 years ago
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