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dolphi86 [110]
3 years ago
11

Evaluate the following expression when x = 3 and y = 4:

Mathematics
2 answers:
Alisiya [41]3 years ago
6 0
Answer: 14.6


Explanation:

\cfrac{x^2 + y^3}{2+ x}

When x = 3, y - 4,

\cfrac{3^2 + 4^3}{2+ 3}  =  \cfrac{73}{5} = 14 \cfrac{3}{5} = 14.6
OLEGan [10]3 years ago
3 0

\dfrac{ {3}^{2} +  {4}^{3}  }{2 + 3}  \\  =  \dfrac{9 + 64}{5}  \\  =  \dfrac{73}{5}  \\  = 14.6

Answer is C.

Hope this helps. - M
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lutik1710 [3]
I think you mean b is not equal to 0.

We have that 11.424242... = 11 + 0.424242...
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