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Nuetrik [128]
3 years ago
7

Find the area of the pink sector(s). The diameter is 8.

Mathematics
1 answer:
Afina-wow [57]3 years ago
5 0
First we would need the sector formula which is: 丌r^2× angle/360

To find the radius,we would have to divide the diameter by two,which is:
l8÷2=4 units

We would also need to find the total valuenof angles of pink sectors:
41+44+47=132°

As it's not mentioned,let's take pi as 3.14.

In this case,it would be:

(3.14)(4)^2(132°/360°)
=16(3.14)(11/36)
=18.4213..
≈18.4 sq. units

Thus the answer us D.18.4 units.

Hope it helps!
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Whats the surface area of a cylinder with height of 12in.and the radius is 4in​
emmainna [20.7K]

Answer:

401.92 in²

Step-by-step explanation:

S.A. = 2πr²+2πrh

S.A. = 2π4²+2π4·12

S.A. = 100.48 + 301.44

S.A. = 401.92 in²

7 0
3 years ago
Find the measure of angle eight in each triangle round each answer to the nearest 10th
vlada-n [284]

Answer:

# m∠A = 65.3°

# m∠A = 25.8°

# m∠A = 22.7°

Step-by-step explanation:

* Lets revise the trigonometry function to solve the problem

- In any right angle triangle:

# The side opposite to the right angle is called the hypotenuse

# The other two sides are called the legs of the right angle

* If the name of the triangle is ABC, where B is the right angle

∴ The hypotenuse is AC

∴ AB and BC are the legs of the right angle

- ∠A and ∠C are two acute angles

- For angle A

# sin(A) = opposite/hypotenuse

∵ The opposite to ∠A is BC

∵ The hypotenuse is AC

∴ sin(A) = BC/AC

# cos(A) = adjacent/hypotenuse

∵ The adjacent to ∠A is AB

∵ The hypotenuse is AC

∴ cos(A) = AB/AC  

# tan(A) = opposite/adjacent

∵ The opposite to ∠A is BC

∵ The adjacent to ∠A is AB

∴ tan(A) = BC/AB

* Lets solve the problems

# In Δ ABC

∵ m∠B = 90°

∵ AB = 2.3 ⇒ adjacent to angle A

∵ BC = 5 ⇒ apposite to angle A

- To find m∠A use the tangent function because we have opposite

  and adjacent sides

∴ tan A = BC/AB

∴ tan A = 5/2.3 ⇒ use tan^-1 to find m∠A

∴ m∠A = tan^{-1}\frac{5}{2.3}=65.29756

* m∠A = 65.3°

# In Δ ABD

∵ m∠B = 90°

∵ AB = 5.4 ⇒ adjacent to angle A

∵ DA = 6 ⇒ the hypotenuse

- To find m∠A use the cosine function because we have adjacent

  and hypotenuse sides

∴ cos A = AB/DA

∴ cos A = 5.4/6 ⇒ use cos^-1 to find m∠A

∴ m∠A = cos^{-1}\frac{5.4}{6}=25.84193

* m∠A = 25.8°

# In Δ ABE

∵ m∠B = 90°

∵ EB = 2.4 ⇒ opposite to angle A

∵ EA = 6.8 ⇒ the hypotenuse

- To find m∠A use the sine function because we have opposite

  and hypotenuse sides

∴ sin A = EB/EA

∴ sin A = 2.4/6.8 ⇒ use sin^-1 to find m∠A

∴ m∠A = sin^{-1}\frac{2.4}{6.8}=22.6673

* m∠A = 22.7°

3 0
3 years ago
Solve for each unknown angle measure given that ℓ1∥ℓ2.
r-ruslan [8.4K]

Answer:

Step-by-step explanation:

the other person might be right sorry man

8 0
3 years ago
Read 2 more answers
What is 1,345 /99 rounded to the nearest integer?
mylen [45]
It's 14 because when you divide you get 13 with a remainder of 58 which is over half of 99 which means that you round up to 14
3 0
3 years ago
Suppose a rope is nailed to a pole 35 meters above the ground and extended away from the base of the pole. The distance from the
motikmotik

Answer:

B.  \:  \boxed{66.8}

Step-by-step explanation:

to \: solve \: this \: little \: poblem : we \:apply \: the \: pythagrean \: rule \to \\  \boxed{SOH} \boxed{CAH} \boxed{TOA} \to \\ we \: are \: been \: given :  \to \\ the \:  \boxed{opp }\: of \: the \: required \: angle \:  = 35. \\ the \:  \boxed{adj }\: of \: the \: required \: angle \:  = 15. \\  now \: lets \: apply \: \boxed{TOA}\to \: \tan( \theta)  =  \frac{opp}{adj}   \to\\  \tan( \theta)  =  \frac{opp}{adj}  =  \frac{35}{15}  = 2.3333333333 \\  \theta =  \tan {}^{ - 1} (2.3333333333)  \\   \boxed{\theta = 66.80}

♨Rage♨

6 0
3 years ago
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