Let's say a = number of ordered soups, b = number of ordered sandwiches.
Then 4.5a + 7.75b = 113.50, and a and b are integers between 0 and 18 inclusive.
How do we tackle this? If all ordered soup, the cost would be $81, so we'll have at least 4 sandwiches. If all ordered sandwich, the cost would be $139.5, so at most 15 sandwiches were ordered. You also know an even number of sandwiches was ordered, to let the price end at 50 cent.
If you brute-force from 4,6,8,10,12 to 14 sandwiches, you find the answer at 10 sandwiches and 8 soups.
10*7.75 + 8*4.50 = 113.50
Answer: Im pretty sure its 143 if it was degrees but yeah
Step-by-step explanation:
Solution :
To claim to be tested is whether "the mean salary is higher than 48,734".
i.e. μ > 48,734
Therefore the null and the alternative hypothesis are
and 
Here, n = 50
s = 3600
We take , α = 0.05
The test statistics t is given by
t = 2.15
Now the ">" sign in the 
sign indicates that the right tailed test
Now degree of freedom, df = n - 1
= 50 - 1
= 49
Therefore, the p value = 0.02
The observed p value is less than α = 0.05, therefore we reject 
. Hence the mean salary that the accounting graduates are offered from the university is more than the average salary of 48,734 dollar.
Step-by-step explanation:
Answer: The inverse is f^-1 (x) = x - 11
