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lidiya [134]
4 years ago
13

Use the discriminant to determine the number and type of solutions for the following equation. 12x2 + 10x + 5 = 0

Mathematics
2 answers:
alex41 [277]4 years ago
5 0
Zero real solutions I just did the test
Paul [167]4 years ago
4 0
Discriminant D is given by:
D=b²-4ac
Implication of discriminant is as follows:

D<0 two zeros that are complex conjugate
D=0 one real zero of multiplicity 2
D>0 two distinct real zers
D= (+ve perfet square)  two distinct rational zeros
From:
12x^2+10x+5=0
plugging in the equation we get:
10²-4×12×5
=100-240
=-140
thus
D<0

Answer is: 
<span>A two irrational solutions </span>
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HELPP please ??? I’ll appreciate it a lot .
victus00 [196]

Answer:   \sqrt{41}

On a keyboard you would type sqrt(41)

===========================================

Work Shown:

\text{point L} = (x_1, y_1) = (2,-1)\\\\\text{point N} = (x_2, y_2) = (7,-5)\\\\

d = \text{distance from L to N}\\\\d = \sqrt{ (x_1-x_2)^2 + (y_1-y_2)^2 } \ \text{ ... distance formula}\\\\d = \sqrt{ (2-7)^2 + (-1-(-5))^2 }\\\\d = \sqrt{ (2-7)^2 + (-1+5)^2 }\\\\d = \sqrt{ (-5)^2 + (4)^2 }\\\\d = \sqrt{ 25 + 16 }\\\\d = \sqrt{ 41 }\\\\

----------

A slight alternative is to plot the point M(2,-5) to form right triangle LMN. The 90 degree angle is at point M.

The legs are of length LM = 4 and MN = 5, which are found by subtracting the x coordinates together and the y coordinates together (or you can count the spaces). From there, use the Pythagorean theorem to get the hypotenuse LN.

The distance formula is an altered version of the Pythagorean theorem.

5 0
3 years ago
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Write an expression for the calculation 47 minus 3 times the diffrence of 15 and 2.
valina [46]
the expression is (47-3)*(15-2)
7 0
4 years ago
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The Martins drove 210.5 miles on the first day of their trip and 135.8 miles the second day. How many more miles did they drive
Ksenya-84 [330]

Answer: the answer is A

Step-by-step explanation:

3 0
3 years ago
Given: Circle M with inscribed Angle K J L and congruent radii JM and ML Prove: mAngle M J L = One-half (measure of arc K L) Cir
Luda [366]

Answer:

We need to demontrate

m \angle MJL = \frac{1}{2}arc(KL)

As you can see in the figure below, angle MJL is an inscribed angle for Circle M, that means we can use the inscribed angle theorem to demonstrate the proposition above.

<h3>Therorem.</h3>

<em>The angle formed by two intersecting chords with vertex on the circumference is equal to one-half of the intercepted arc.</em>

<em />

Notice that the theorem says a chord. However, a diameter is a chord by definition, because a chord is a segment that unites to points of the circumference, and a diameter does that too.

Therefore, based on the inscribed angle arc theorem, we have

m \angle MJL = \frac{1}{2}arc(KL)

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3 years ago
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Vsevolod [243]

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8.4

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3 years ago
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