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3 years ago

(QUICK QUESTION) If you have 18 credits In the 12th grade Is it possible to get 23 by June 2019?? In one semester

Mathematics

2 answers:

V125BC [204]3 years ago

8 0

Answer:

Its all up to you and how hard you are willing to work to get that may credits in one semester. But you could do it. Hope that helped!

Step-by-step explanation:

azamat3 years ago

3 0

Its all up to you and how hard you are willing to work to get that may credits in one semester. But you could do it. Hope that helped!

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Write a polynomial equation in standard form with the following zeros<br><br> 4,9

Evgen [1.6K]

Answer:

y = x² - 13x + 36

Step-by-step explanation:

Given the zeros x = 4 and x = 9, then the corresponding factors are

(x - 4) and (x - 9)

The polynomial is then the product of the factors

y = (x - 4)(x - 9) ← expand using FOIL

y = x² - 13x + 36

3 0

3 years ago

How do I do this ixl

svetlana [45]

The anwser that I know of is 6x+2

8 0

3 years ago

In a list of households, own homes and do not own homes. Five households are randomly selected from these households. Find the p

hichkok12 [17]

Answer:

The probability of success for this case would be:

$p =\frac{9}{15}= 0.6$ representing the proportion of homes that are own homes

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=15, p=0.6)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

And we want this probability:

$P(X=3)$

And uing the probability mass function we got:

$P(X=3)= 15C3 (0.6)^3 (1-0.6)^{15-3}= 0.00165$

Step-by-step explanation:

Adduming the following info: In a list of 15 households, 9 own homes and 6 do not own homes. Five households are randomly selected from these 15 households. Find the probability that the number of households in these 5 own homes is exactly 3.

Round your answer to four decimal places

P (exactly 3)=

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

The probability of success for this case would be:

$p =\frac{9}{15}= 0.6$ representing the proportion of homes that are own homes

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=15, p=0.6)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

And we want this probability:

$P(X=3)$

And uing the probability mass function we got:

$P(X=3)= 15C3 (0.6)^3 (1-0.6)^{15-3}= 0.00165$

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3 years ago

Can you help me out? In a test

NikAS [45]

Answer:

Step-by-step explanation:

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3 years ago

Plz help ill give u brainlist

Sindrei [870]

He needs 25 cm^3 of sand

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3 years ago