Question

Find the equation of the line perpendicular to 2y-5=3x+7 that passes through the point (11,1)

Answer 1

Y= -2/3x + 8 1/3

Because:

First I found the equation, y=3/2x+12
Next, to find the perpendicular equation heres what you do. The yint does not matter, it changes completely so we should just get rid of it to equal. y=3/2x Next, we changed the slope. For perpendicular lines, we flip the fraction then make it the opposite (negative to positive or positive to negative) Which would make this slope to now be -2/3 Filter that into the equation to be, y=-2/3x Now to find the yint we use this point, (11,1) We multiple the slope by the first number 11. 11 times -2/3x equals -7 1/3
The yint is the number that you need to add for -7 1/3 to equal 1. Because 1 is the second number of (11,1) This number is 8 1/3 so,

y= -2/3x + 8 1/3

Hope I wasnt too confusing