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love history [14]
3 years ago
7

Helpppppppppppppppppppppppp

Mathematics
1 answer:
stepladder [879]3 years ago
7 0

the answer is b i did the math it checks out

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The sum of two positive integers, a and b, is at least 30. The difference of the two integers is at least 10. If b is the greate
spin [16.1K]
A+b > 30

b-a > 10

hope it helps :)
5 0
3 years ago
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Divide the following fractions and reduce to lowest terms 2/3 divided by 4/5
pshichka [43]
Well to divide 2 fraction you first have to find a least common number between the 2 bottom numbers in the fractions, we know automaticall that 15 fits in both the 3 and the 5. now u have to find out what to multiply by each number to get 15, for example what number do you multiply by 3 to get 15?? well it will be 5, so go ahead and multiply it by the fraction (note that what you do  in the bottom you have to do in the top) this will give you 10/15, because I multiplied the top and bottom number by 5... lets try the other one what number do you multiply by 5 to get 15?? well it will be 3 so go ahead and multiply that to get 12/15.. now add the top numbers (note that the bottoms always stay the same, you never add or subtract them) when you do you will get 22/15, now you have to see if you can simplify it any further in this case you can't so your final answer is 22/15

Hope this helps
5 0
3 years ago
For centuries, mathematics seemed to exist in service to the natural sciences. Many of the great mathematical breakthroughs, lik
adell [148]

Answer:

b,d

Step-by-step explanation:

4 0
2 years ago
Write the following sum using summation notation -2/5+3/6-4/7........11/14
horrorfan [7]

Answer:

\sum_{n=1}^{10}(-1)^n\left ( \frac{n+1}{n+4} \right )

Step-by-step explanation:

Given: \frac{-2}{5}+\frac{3}{6}-\frac{4}{7}+...+\frac{11}{14}

To write: the given expression using summation notation

Solution:

Summation notation helps to write a long sum as a single expression.

In the summation notation, the variable \sum is called the index of summation.

Let x_1,x_2,x_3,...,x_n denote a set of n numbers.

Then in summation notation,

x_1+x_2+x_3+...+x_n=\sum_{i=1}^{n}x_i

\frac{-2}{5}=(-1)^1\left ( \frac{1+1}{1+4} \right )\\\frac{3}{6}=(-1)^2\left ( \frac{2+1}{2+4} \right )\\\frac{-4}{7}=(-1)^3\left ( \frac{3+1}{3+4} \right )\\.\\.\\.\\\frac{11}{14}=(-1)^10\left ( \frac{10+1}{10+4} \right )\\\therefore \frac{-2}{5}+\frac{3}{6}-\frac{4}{7}+...+\frac{11}{14}=\sum_{n=1}^{10}(-1)^n\left ( \frac{n+1}{n+4} \right )

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3 years ago
What are the coordinates of point G of the pre-image?
zaharov [31]

Answer:

B

Step-by-step explanation:

8 0
3 years ago
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