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schepotkina [342]
4 years ago
5

An employee working in a machine shop is exposed to three different sources which emit noises at 81 dB, 91 dB, and 88 dB. What i

s the combined noise level exposure?

Mathematics
1 answer:
leonid [27]4 years ago
5 0
Hello,
Please, see the attached file.
Thanks.

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PLEASE HELP MEEEEEE PLEASEEEEEEEE!!!!!! IM TIMED
blsea [12.9K]
The answer is d 160 tickets.
6 0
3 years ago
Read 2 more answers
The cost of 5kg of rice is Rs.425. find the cost of 1kg of rice ​
DaniilM [7]

Answer:

Rs 85

Step-by-step explanation:

Cost of 5kgs of rice = Rs 425

Cost of 1 kg of rice = 425/5

= Rs 85

So, the cost of a kg of rice is Rs 85

8 0
2 years ago
Identify a pattern in this list of numbers 1,4,9,16,25,36
m_a_m_a [10]
Start by subtracting the last two numbers
6 0
3 years ago
there are some nickles dimes and quaters in a large pinnhy bank for every 2 nickles there 3 dimes for every 2 dimes there five q
atroni [7]

100 nickels 150 dimes 250 quarters

Step-by-step explanation:

Trust me

4 0
3 years ago
A second particle, Q, also moves along the x-axis so that its velocity for 0 £ £t 4 is given by Q t cos 0.063 ( ) t 2 v t( ) = 4
Vladimir79 [104]

Answer:

The time interval when V_Q(t) \geq 60  is at  1.866 \leq t \leq 3.519

The distance is 106.109 m

Step-by-step explanation:

The velocity of the second particle Q moving along the x-axis is :

V_{Q}(t)=45\sqrt{t} cos(0.063 \ t^2)

So ; the objective here is to find the time interval and the distance traveled by particle Q during the time interval.

We are also to that :

V_Q(t) \geq 60    between   0 \leq t \leq 4

The schematic free body graphical representation of the above illustration was attached in the file below and the point when V_Q(t) \geq 60  is at 4 is obtained in the parabolic curve.

So, V_Q(t) \geq 60  is at  1.866 \leq t \leq 3.519

Taking the integral of the time interval in order to determine the distance; we have:

distance = \int\limits^{3.519}_{1.866} {V_Q(t)} \, dt

= \int\limits^{3.519}_{1.866} {45\sqrt{t} cos(0.063 \ t^2)} \, dt

= By using the Scientific calculator notation;

distance = 106.109 m

4 0
3 years ago
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