You're looking for c, so you want to isolate it or get it by itself. To get rid of the /3 you multiply since the opposite of division is multiplication and to get rid of it, you do the opposite (like -9 you would add 9 to get it to 0). Now you are left with -19+c = 24 (the 24 is 8*3 because what you do to one side you do to the other. Now you get c by itself so you add 19 to both sides which leaves you with C= 43. Sorry if this was confusing!
Answer:
3x^2 + 12x + 4y^2 - 8y = 32
Step-by-step explanation:
3(x^2+4x)+4(y^2-2y)=32
At first we have to break the parenthesis to get the variables in normal position. To break those, we have to multiply each with the help of algebraic expression:
or, (3*x^2) + (3 × 4x) + (4 × y^2) - (4 × 2y) = 32
or, 3x^2 + 12x + 4y^2 - 8y = 32
Since the equation does not have anything to add or deduct, therefore, it is the answer.
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Answer:
2. y = 7/2 x -2
3. y = 3/4x-1
Step-by-step explanation:
points (0,-2) (4,12)
slope = (y2-y1)/(x2-x1)
slope = (12--2)/(4-0)
= (12+2)/4
= 14/4 = 7/2
the slope is 7/2 and the y intercept is -2
y = mx+b
y = 7/2 x -2
points (0,-1) (4,2)
slope = (y2-y1)/(x2-x1)
slope = (2--1)/(4-0)
= (2+1)/4
= 3/4
the slope is 3/4 and the y intercept is -1
y = mx+b
y = 3/4x-1
Sarah bought 3 first class tickets and 7 coach tickets.
Step-by-step explanation:
Given,
Number of people = 10
Total amount spent on tickets = $4830
Cost of each coach ticket = $270
Cost of each first class ticket = $980
Let,
x be the number of coach tickets
y be the number of first class tickets
According to given statement;
x+y=10 Eqn 1
270x+980y=4830 Eqn 2
Multiplying Eqn 1 by 270
Subtracting Eqn 3 from Eqn 2
Dividing both sides by 710
Putting y=3 in Eqn 1
Sarah bought 3 first class tickets and 7 coach tickets.
Keywords: linear equation, elimination method
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