Question

If ΔABC ≅ ΔEDF where the coordinates of A(0, 2), B(2, 4), and C(2, −1), what is the measure of DF?

Answer 1

BC = DF

(-1-4)^2 + (2-2)^ 2

(-5)^2 + (0)^2
Square root 25 is 5

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Answer 2

Answer:

C. 5

Step-by-step explanation:

Since Triangle ABC is congruent to EDF it mean that the sides are the same so the length of BC is congruent to the length of DF:

distance formula:

d = √(x2 - x1)^2 + (y2 - y1)^2

d = √(2 - 2)^2 + (-1 - 4)^2

d = √(0)^2 + (-5)^2

d = √0 + 25

d = √25

d = 5