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3 years ago

If ΔABC ≅ ΔEDF where the coordinates of A(0, 2), B(2, 4), and C(2, −1), what is the measure of DF?

2 answers:

tatiyna3 years ago

5 0

BC = DF

(-1-4)^2 + (2-2)^ 2

(-5)^2 + (0)^2
Square root 25 is 5

C is the answer. Can you mark me as brianliest? Really appreciate it!

allsm [11]3 years ago

4 0

Answer:

C. 5

Step-by-step explanation:

Since Triangle ABC is congruent to EDF it mean that the sides are the same so the length of BC is congruent to the length of DF:

distance formula:

d = √(x2 - x1)^2 + (y2 - y1)^2

d = √(2 - 2)^2 + (-1 - 4)^2

d = √(0)^2 + (-5)^2

d = √0 + 25

d = √25

d = 5

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Can someone help me? Brainliest + Points!

iris [78.8K]

Answer:

D. $\frac{2}{5}$

Step-by-step explanation:

Since we know that the odds of an events can be found by dividing the probability that an event will occur by the probability that the event will not occur.

$\text{Odds of an event}=\frac{\text{Probability that event will occur}}{\text{Probability that event will not occur}}$

Probability of an event not occurring can be found by subtracting probability of the event occurring from 1.

$\text{Odds of an event}=\frac{\text{Probability that event will occur}}{1-\text{Probability that event will occur} }$

We have been given that probability of an event is 2/7.

Upon substituting our given values in above formula we will get,

$\text{Odds of the given event}=\frac{\frac{2}{7}}{1-\frac{2}{7}} }$

$\text{Odds of the given event}=\frac{\frac{2}{7}}{\frac{7-2}{7}} }$

$\text{Odds of the given event}=\frac{\frac{2}{7}}{\frac{5}{7}} }$

$\text{Odds of the given event}=\frac{2}{7}\times \frac{7}{5}$

$\text{Odds of the given event}=\frac{2}{5}$

Therefore, the odds of the same event are $\frac{2}{5}$ and option D is the correct choice.

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Answer:

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Step-by-step explanation:

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