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defon
3 years ago
5

In the figure shown, lines 1 and 2 are parallel.

Mathematics
1 answer:
Sav [38]3 years ago
7 0

Answer:

Step-by-step explanation:

8=09

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Find the other two vertices of a square with one vertex (0, 0) and another vertex (4, 2). Can you find another answer?
Margarita [4]

It is given that two vertices of square are (0,0) and (4,2).

Now the problem is that you haven't given that whether these two vertices are adjacent vertices or opposite vertices of the square.

1. By Supposing that these two are adjacent vertices of Square

The third vertex will be at (-4,2) which lies in third quadrant.

Suppose the coordinate of fourth vertex be (x,y).

Mid point of line joining (4,2) and (-4,2) is{ [4+(-4)]/2,(2+2)/2} is (0,2).

Mid point of line joining (x,y) and (0,0) is (x/2,y/2).

Since diagonals of square bisect each other,

∵ x/2=0

⇒x=0

and

y/2=2

⇒y=4

So, The Coordinate of  fourth vertex is (0,4).

Now coming back to second condition if these are two opposite vertex of Square.

Let the third coordinate be (a,b).

Length of diagonal=\sqrt{(4-0)^2+(2-0)^2}=\sqrt20=2\sqrt5

Now,let side of Square be A.

Then length of Diagonal of square =√2 A

⇒√2 A=2√5

⇒A =√10

As third vertex is (a,b).

Using distance formula

a² + b²=10  -------------(1)

(a-4)²+ (b-2)²=10  --------------(2)

Solving expression (1) and (2), we get

⇒a²+ b²=(a-4)² +(b-2)²

⇒2a + b =5

⇒b=5-2a

Putting the value of b in (1),we get

⇒a² +(5-2a)²=10

⇒a²+25+4a²-20a =10

⇒5a²-20a+15=0

⇒a² - 4a + 3=0

Splitting the middle term,we get

⇒(a-3)(a-1)=0

⇒a=3  ∧  a=1

we get b=5-2×1=3 and b=5-2×3=5-6=-1

So,the other vertex are (1,3) and(3,-1).





3 0
3 years ago
Find the GCF of the following terms. <br> 16xy^3 , 20x^2y^2 , -4x^2y
Ivanshal [37]
16xy^3=4xy\cdot4y^2\\\\20x^2y^2=4xy\cdot5xy\\\\-4x^2y=4xy\cdot(-x)\\\\GCF(16xy^3;\ 20x^2y^2;\ -4x^2y)=4xy
7 0
3 years ago
Ayuda es urgente ya lalalalalalalalalalal​
Crank

Answer:

no se ve la imagen perdón no te puedo ayudar

8 0
3 years ago
11+4 (x+7) 2nd power when x=2
monitta
<span>11+4 (x+7)^2
Substitue 2 for x
</span><span>11+4 (2+7)^2
Multiply the numbers inside of the parenthesis by the exponent
11+4 (4+49)
Add 4 to 59
11+4 (54)
Add 4 to 11
15(54)
Multiply
Final Answer: 810</span>
6 0
3 years ago
Read 2 more answers
What is the area of a regular pentagon with a perimeter of 115cm?
shusha [124]
About 480.4 or 480.4262466 if you need the whole thing
3 0
3 years ago
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