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jeyben [28]
4 years ago
8

Factor 18p-3618p−3618, p, minus, 36 to identify the equivalent expressions. Choose 2 answers: Choose 2 answers:

Mathematics
2 answers:
lisabon 2012 [21]4 years ago
5 0

Answer:

18(p-2)

Step-by-step explanation:

We want to factor 18p-36

We know that the greatest common factor is 18.

So we can rewrite to obtain:

18*p-18*2

We factor the GCF to obtain:

18(p-2)

Therefore 18p-36=18(p-2)

Therefore the equivalent expression to 18p-36 is 18(p-2)

Ilya [14]4 years ago
5 0

Answer:

18(p-2) and 2(9-18)

Step-by-step explanation:

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8 0
3 years ago
A shipment of 50 precision parts including 4 that are defective is sent to an assembly plant. The quality control division selec
natali 33 [55]

Answer:

0.3968 = 39.68% probability this shipment passes inspection.

Step-by-step explanation:

The parts are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

50 parts means that N = 50

4 defective means that k = 4

10 are chosen, which means that n = 10

What is the probability this shipment passes inspection?

Probability that none is defective, so:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 0) = h(0,50,10,4) = \frac{C_{4,0}*C_{46,10}}{C_{50,10}} = 0.3968

0.3968 = 39.68% probability this shipment passes inspection.

6 0
3 years ago
A study of the amount of time it takes a mechanic to rebuild the transmission for a 2005 Chevrolet Cavalier shows that the mean
Misha Larkins [42]

Answer: 0.9608

Step-by-step explanation:

Given : A study of the amount of time it takes a mechanic to rebuild the transmission for a 2005 Chevrolet Cavalier shows that

Mean :\mu=8.4\text{ hours}

Standard deviation : \sigma=1.8\text{ hours}

Sample size : n=40

Let \overline{x} be the sample mean.

The formula for z-score in a normal distribution :

z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

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Hence, the probability that their mean rebuild time is less than 8.9 hours is 0.9608 .

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3 years ago
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