Let a represent the # of adults and s the # of students attending.
Since 938 people attended, a + s = 938, or s = 938 - a
Ticket sales to adults brought in $2.00(a) and ticket sales to students brought in $0.75s. We must solve for a and s.
Let's do that via substitution of 938 - a for s:
$2.00a + $0.75(938-a) = $1109 (which was the total sales revenue)
Then 2.00a + 0.75(938) - 0.75a = 1109. Combining like terms, we get:
1.25a = 1109 - 0.75(938), or
1.25a = 1109 - 703.5, or:
1.25 a = 405.50
Dividing both sides by 1.25, we get:
a = 324.4
Let a represent the # of adults and s the # of students attending.
Since 938 people attended, a + s = 938, or s = 938 - a
Ticket sales to adults brought in $2.00(a) and ticket sales to students brought in $0.75s. We must solve for a and s.
Let's eliminate s. Solve a + s = 938 for a: a = 938 - s.
Then $2(938 - s) + $0.75s = $1109.
This simplifies to $1876 - $2s + $0.75s = $1109, or
$1186 - $1109 = $1.25s. Solving for s, we get s = 613.6
I did this problem twice, once by eliminating a and once by eliminating s. Both times the number of students came out to be 613.6 and the number of adults 324.4. This makes zero sense, since such a count MUST be integer.
Would you please double check to ensure that you've copied down this problem correctly. Thank you.
