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3 years ago

8

DJ movie collection is constantly crying you already had a large number of movies but his friend just gave him a donation that w

as five more than half a number of movies that he had already had if he now has 80 movies how many did he start with write an equation

1 answer:

Veronika [31]3 years ago

8 0

Step-by-step explanation:

lol! thanks for the point

hehehehehehehe

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The maximum weight that a rectangular beam can support varies jointly as its width and the square of its height and inversely as

NISA [10]

$\bf \qquad \qquad \textit{joint compound proportional variation} \\\\ \begin{array}{llll} \textit{\underline{y} varies directly with \underline{x}}\\ \textit{and inversely with \underline{z}} \end{array}\implies y=\cfrac{kx}{z}\impliedby \begin{array}{llll} k=constant\ of\\ \qquad variation \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{\textit{W varies jointly as its width, squared heght and inversely with length}}{W=\cfrac{wh^2}{L}}$

$\bf \textit{now we also know that }~~ \begin{cases} w=\frac{1}{4}\\ h=\frac{1}{3}\\ L=12\\ W=30 \end{cases}\implies 30=\cfrac{~~k\frac{1}{4}\left( \frac{1}{3} \right)^2~~}{12} \\\\\\ 360=\cfrac{k}{36}\implies 12960=k~\hfill \boxed{W=\cfrac{12960wh^2}{L}}$

$\bf \textit{when } \begin{cases} w=\frac{1}{4}\\ h=\frac{1}{2}\\ L=12 \end{cases}\textit{ what is \underline{W}?}\qquad W=\cfrac{12960\left( \frac{1}{4} \right)\left(\frac{1}{2} \right)^2}{12} \\\\\\ W=1080\left( \cfrac{1}{4} \right)\left( \cfrac{1}{4} \right)\implies W=1080\cdot \cfrac{1}{16}\implies W=\cfrac{135}{2}\implies W=67\frac{1}{2}$

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3 years ago

Simplify the expression <br> (Show work if you can)

Alborosie

This equation can be written as

(v-8)(v+5)/ (v-8)(v-3)
= v+5/v-3

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IrinaK [193]

Answer:

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Heyyyyy
Hope this helps!
~Nadia~

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