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agasfer [191]
3 years ago
10

Tracy is running in a 5.25km race on Saturday.

Mathematics
2 answers:
Tomtit [17]3 years ago
7 0
How amny times more is marathon than tracy's race
tracy t imes x=42
5.25 times x=42
divide both side by 5.25 (since 5.25/5.25=1)
x=8

answe ris 8 times
saul85 [17]3 years ago
5 0

Answer:

x-8

Step-by-step explanation:

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A grower believes that one in five of his citrus trees are infected with the citrus red mite. How large a sample should be taken
kotegsom [21]

Answer: 68

Step-by-step explanation:

Formula for sample size when prior estimate of population proportion (p) is available:  n=p(1-p)(\dfrac{z^*}{E})^2

, where z*= critical-value.

E= Margin of error.

Let p be the population proportion of  trees are infected with the citrus red mite.

As per given , we have

p=\dfrac{1}{5}=0.2

E= ± 0.08

The critical z-value corresponding to 90% confidence level = z*=1.645

Substitute all the values in the above formula , we get

Required sample size  :n=(0.2)(1-0.2)(\dfrac{(1.645)}{0.08})^2

\Rightarrow\ n=(0.2)(0.8)(20.5625)^2

\Rightarrow\ n=0.16(422.81640625)\\\\\Rightarrow\ n=67.650625\approx68 [Rounded to next integer.]

Thus, the minimum sample size should be taken =68

6 0
3 years ago
Pls help me in this question it is really needed
DaniilM [7]

Answer:

6 1/8 ×10 2/7= 60

60÷2 1/3= 30

The answer:

30

8 0
3 years ago
Solve the equation for x. x + 3 /6 = x - 6/ 3 A) 9 B) 12 C) 15 D) 18
Strike441 [17]

Answer:

a

Step-by-step explanation:

7 0
4 years ago
HELP MEEEE<br> How do you add and subtract functions?
nata0808 [166]

Answer:

To add or subtract functions, just add or subtract the values at each point where it makes sense. If the functions are given by formulas, you can just add or subtract the formulas (it doesn't matter whether you plug in values before or after).

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Solve.<br><br> x^-9 y^3 / x^-7 y^8
aniked [119]

\dfrac{x^{-9}y^3}{x^{-7}y^8}=x^{-9-(-7)}y^{3-8}=x^{-2}y^{-5}=\dfrac{1}{x^2y^5}\\\\Used:\\\\\dfrac{a^n}{a^m}=a^{n-m}\\\\a^{-n}=\dfrac{1}{a^n}

3 0
3 years ago
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