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anygoal [31]
3 years ago
12

A family ordered some candy bars and bags of chips for snacking. The number of candy bars was twice as much as the number of bag

s of chips. If the family spent a total of $5.50, how many bags of chips did the family buy?
Mathematics
1 answer:
sammy [17]3 years ago
7 0

Answer:

The family bought approximately 2 bags of chips.

Step-by-step explanation:

Given:

Total spent by family = $5.50

We need to find bags of chips did the family buy.

Solution:

Let number of bags of chips bought be 'x'.

Also Given:

The number of candy bars was twice as much as the number of bags of chips.

number of candy bars = 2x

Now we can say that;

Total spent by family is equal to sum of the number of bags of chips bought and number of candy bars.

framing in equation form we get;

x+2x=5.5\\\\3x=5.5

Dividing both side by 3 we get;

\frac{3x}{3}=\frac{5.5}{3}\\\\x=1.83\approx2

Hence the family bought approximately 2 bags of chips.

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69;) yes yes yes yes

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Anuta_ua [19.1K]

Option A:

\left(x^{4}\right)\left(3 x^{3}-2\right)\left(4 x^{2}+5 x\right)=12 x^{9} +15 x^{8} -  8 x^{6}-10 x^{5}

Solution:

Given expression \left(x^{4}\right)\left(3 x^{3}-2\right)\left(4 x^{2}+5 x\right).

To find the product of the above expression:

\left(x^{4}\right)\left(3 x^{3}-2\right)\left(4 x^{2}+5 x\right)

First multiply first two factors with each term.

           =(x^{4} \times 3 x^{3}- x^{4} \times 2 ) \left(4 x^{2}+5 x\right)

Using exponent rule: a^m \cdot a^n=a^{m+n}

            =(3 x^{7}- 2x^{4} ) \left(4 x^{2}+5 x\right)

Now multiply these two factors with each term.

            =3 x^{7} (4 x^{2}+5 x)- 2x^{4} \left(4 x^{2}+5 x\right)

            =(4 x^{2} \times 3 x^{7} +5 x \times 3 x^{7} )-  \left(4 x^{2} \times 2x^{4}+5 x \times 2x^{4}\right)

Using exponent rule: a^m \cdot a^n=a^{m+n}

            =(12 x^{9} +15 x^{8} )-  (8 x^{6}+10 x^{5})

           =12 x^{9} +15 x^{8} -  8 x^{6}-10 x^{5}

\left(x^{4}\right)\left(3 x^{3}-2\right)\left(4 x^{2}+5 x\right)=12 x^{9} +15 x^{8} -  8 x^{6}-10 x^{5}

Hence option A is the correct answer.

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Please help with answers
mart [117]
The answer to number 9 is 6, 1.

The answer to number 11 is 28.

The answer to number 10 is a hexagon.

The answer to number 12 is 27 and 36.

Hope this helps!

-SummerBreaker ;)
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elena55 [62]
The answer is D, y= 2x-1
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3 years ago
An advertisement for the state fair will be painted on one of four silos along the highway into town. The silos are in the shape
fredd [130]
<h3>Answer: Silo D</h3>

===============================================

How I got that answer:

r = radius

h = height

LA = lateral surface area of cylinder

LA = 2*pi*r*h

Let's find the lateral surface area of each silo. The smallest lateral surface area will lead to the lowest total cost.

-------------

Silo A

LA = 2*pi*r*h

LA = 2*pi*6*60

LA = 720pi

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Silo B

LA = 2*pi*r*h

LA = 2*pi*8*50

LA = 800pi

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Silo C

LA = 2*pi*r*h

LA = 2*pi*10*34

LA = 680pi

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Silo D

LA = 2*pi*r*h

LA = 2*pi*12*20

LA = 480pi

-------------

If we ignore the "pi" terms for each of the four answers above, we see that 480 is the smallest value. Silo D has the smallest lateral surface area at 480pi square feet.

-------------

Side note: to determine the total cost, you multiply the surface area by the cost per square foot ($1.20)

For example, the total cost to paint silo D is

cost = (surface area)*(price per square foot)

cost = (480*pi)*(1.20)

cost = 1809.557

cost = 1809.56

This section is optional as your teacher isnt requiring you to find the actual costs, but rather just the silo with the least amount of area. You could go the longer route to find each surface area, compute the total cost, and then compare the total costs. You should find that silo D's cost is the lowest.

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