What is an equation of the line that passes through the point (-4,5) and is

981 rounded to nearest 100

sergey [27]

Answer: 1000

Step-by-step explanation:

9 8 1

Hundred tens one

The question is asking for to round to the nearest hundred (100) which means is rounding to [9] in this question.

The number of the place before the hundreds place is [8] on the tens place.

When numbers are greater than or equal to 5, you round up a digit.
When numbers are less than 5, you round down a digit.

[8] is greater than 5, so you round 9 up. When rounding 9 up, you get 10.

<h2>So, the final number will be 1000</h2>

6 0

3 years ago

onsider the following hypothesis test: H 0: 50 H a: > 50 A sample of 50 is used and the population standard deviation is 6. U

kondaur [170]

Answer:

a) z(e) > z(c) 2.94 > 1.64 we are in the rejection zone for H₀ we can conclude sample mean is great than 50. We don´t know how big is the population .We can not conclude population mean is greater than 50

b) z(e) < z(c) 1.18 < 1.64 we are in the acceptance region for H₀ we can conclude H₀ should be true. we can conclude population mean is 50

c) 2.12 > 1.64 and we can conclude the same as in case a

Step-by-step explanation:

The problem is concerning test hypothesis on one tail (the right one)

The critical point z(c) ; α = 0.05 fom z table w get z(c) = 1.64 we need to compare values (between z(c) and z(e) )

The test hypothesis is:

a) H₀ ⇒ μ₀ = 50 a) Hₐ μ > 50 ; for value 52.5

b) Hₐ μ > 50 ; for value 51

c) Hₐ μ > 50 ; for value 51.8

With value 52.5

The test statistic z(e) ??

a) z(e) = ( μ - μ₀ ) /( σ/√50) z(e) = (2.5*√50 )/6 z(e) = 2.94

2.94 > 1.64 we are in the rejected zone for H₀ we can conclude sample mean is great than 50. We don´t know how big is the population .We can not conclude population mean is greater than 50

b) With value 51

z(e) = ( μ - μ₀ ) /( σ/√50) ⇒ z(e) = √50/6 ⇒ z(e) = 1.18

z(e) < z(c) we are in the acceptance region for H₀ we can conclude H₀ should be true. we can conclude population mean is 50

c) the value 51.8

z(e) = ( μ - μ₀ ) /( σ/√50) ⇒ z(e) = (1.8*√50)/ 6 ⇒ z(e) = 2.12

2.12 > 1.64 and we can conclude the same as in case a

8 0

3 years ago

Graph each absolute value function. State the domain, range, and y-intercept.

lions [1.4K]

Answer:

I. D: $x\in R$

ii. R: $y\le0$

iii. Y-int: $b=-6$

Step-by-step explanation:

i) The given absolute value function is

$y=-3|x+2|$

The domain is all values of x that will make the function defined.

The absolute value function is defined for all real numbers.

The domain is all real numbers.

ii) The range is the values of y for which x is defined.

The given absolute value function is

$y=-3|x+2|$

This function has the vertex at $(-2,0)$ and it is reflected in the x-axis therefore the vertex is the maximum point on the graph.

The y-value of the vertex is the maximum value on the graph.

Hence the range is $y\le0$

iii) To find the y-intercept, we put x=0, into the function to get;

$y=-3|0+2|$

$y=-3|2|$

$y=-3(2)$

$y=-6$

The y-intercept is $b=-6$ or (0,-6)

See graph in attachment.

5 0

2 years ago

How long does it take to travel 240 km at a constant speed of 12 km/h?

timama [110]

All that is necessary in this question is to divide. 240 km divided by 12 is 20. So this means that it would take exactly 20 hrs for someone to drive 240 km in 12 km an hr<span />

4 0

2 years ago

Read 2 more answers

What is the square root of 927

Alina [70]

Answer:

$3\sqrt{103}$