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sergey [27]
3 years ago
10

Inequality in words X > 9

Mathematics
2 answers:
yarga [219]3 years ago
8 0

Answer:

9

Step-by-step explanation:

madam [21]3 years ago
5 0

Answer:

it is 9

Step-by-step explanation:

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Six out of every 100 men are taller than 1.85m.
Andru [333]

Answer:

The probability of the man shorter than 1.85m is 2 in 5.

7 0
3 years ago
In isosceles triangle ABC, AC=BC=20, the measure of angle A=68, and CD is the altitude to side AB. What is CD to the nearest 10t
antiseptic1488 [7]

Answer:

Step-by-step explanation:

Comment

The way the diagram looks when it is drawn is that you are going to need the sine function to solve for the side opposite which is CD.

Formula

Sin(A) = Sin(68 = opposite / hypotenuse     Substitute values.

Solution

sin(68) = altitude (side opposite) / 20       multiply both sides by 20

20*sin(68) = 20* altitude / 20                     substitute for sin(68)

20* 0.9272 = altitude

altitude = 18.5

Answer: 18.5 to the nearest tenth

3 0
1 year ago
2x + 2x2 + 2x3 + ... + 2x<br> O arithmetic<br> O geometric<br> O both<br> O neither
Mkey [24]

Answer:

16 ALB

Step-by-step explanation:

ayudame wey andale

6 0
3 years ago
Find the hypotenuse of an isosceles right triangle when the legs each measure 3\sqrt{x} 2inches.
Tresset [83]

The hypotenuse of the right triangle measures 3 units.

<h3>How to find the hypotenuse?</h3>

Here we know that both legs measure:

L  =\frac{3}{\sqrt{2} }

If we use the Pythagorean theorem, we will see that the hypotenuse H can be written as:

H^2 = (\frac{3}{\sqrt{2} } )^2 +  (\frac{3}{\sqrt{2} } )^2 \\\\H^2 = \frac{9}{2} + \frac{9}{2} = \frac{18}{2} = 9\\\\H = \sqrt{9} = 3

Then we conclude that the hypotenuse of the right triangle measures 9 units.

If you want to learn more about right triangles:

brainly.com/question/2217700

#SPJ1

6 0
1 year ago
1 1/3 - 6/7 is the equation my 11 year old daughter needs help solving. It would be helpful if work can be shown so i can have a
In-s [12.5K]

Answer:

In order to subtract fractions, there must be a common denominator (the number on the bottom of the fraction). 7 and 3 can be multiplied to get 21 (a common factor). To get each fraction to have a denominator of 21, they can be multiplied by 3 and 7 respectively and then subtracted. Attached is an image of the problem worked out. I apologize for the messy handwriting. Hope this helps!

Step-by-step explanation:

8 0
3 years ago
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