Answer:
.201
Step-by-step explanation:
The question is incorrect
the correct question is
A local citizen wants to fence a rectangular community garden. The length of the garden should be at least 110 ft,and the distance around should be no more than 380 ft. Write a system of inequality that model the possible dimensions of he garden. Graph the system to show all possible solutionslet
x---------------> t<span>he length of the garden
</span>y---------------> the wide of the garden
we know that
x>=110
2x+2y <=380---------------> x+y <= 190
Part A) <span>Write a system of inequality that model the possible dimensions of he garden
</span>
the answer part A) is
x>=110
x+y <= 190
Part B) <span>Graph the system to show all possible solutions
using a graph tool
see the attached figure
the solution is the triangle show in the figure
</span><span>the possible solutions of y (wide) would be between 0 and 80 ft
</span>the possible solutions of x (length) would be between 110 ft and 190 ft
Convert them to like denominadors
Is it 905m and 7mm added together to get the blank?
Answer:
111 / 190
Step-by-step explanation:
Let us first compute the probability of picking 2 of each sweet. Take liquorice as the first example. There are 12 / 20 liquorice now, but after picking 1 there will be 11 / 19 left. Thus the probability of getting two liquorice is demonstrated below;
![12 / 20 * 11 / 19 = \frac{33}{95},\\Probability of Drawing 2 Liquorice = \frac{33}{95}](https://tex.z-dn.net/?f=12%20%2F%2020%20%2A%2011%20%2F%2019%20%3D%20%5Cfrac%7B33%7D%7B95%7D%2C%5C%5CProbability%20of%20Drawing%202%20Liquorice%20%3D%20%5Cfrac%7B33%7D%7B95%7D)
Apply this same concept to each of the other sweets;
![5 / 20 * 4 / 19 = \frac{1}{19},\\Probability of Drawing 2 Mint Sweets = 1 / 19\\\\3 / 20 * 2 / 19 = \frac{3}{190},\\Probability of Drawing 2 Humbugs = 3 / 190](https://tex.z-dn.net/?f=5%20%2F%2020%20%2A%204%20%2F%2019%20%3D%20%5Cfrac%7B1%7D%7B19%7D%2C%5C%5CProbability%20of%20Drawing%202%20Mint%20Sweets%20%3D%201%20%2F%2019%5C%5C%5C%5C3%20%2F%2020%20%2A%202%20%2F%2019%20%3D%20%5Cfrac%7B3%7D%7B190%7D%2C%5C%5CProbability%20of%20Drawing%202%20Humbugs%20%3D%203%20%2F%20190)
Now add these probabilities together to work out the probability of drawing 2 of the same sweets, and subtract this from 1 to get the probability of not drawing 2 of the same sweets;
![33 / 95 + 1 / 19 + 3 / 190 = \frac{79}{190},\\1 - \frac{79}{190} = \frac{111}{190}\\\\](https://tex.z-dn.net/?f=33%20%2F%2095%20%2B%201%20%2F%2019%20%2B%203%20%2F%20190%20%3D%20%5Cfrac%7B79%7D%7B190%7D%2C%5C%5C1%20-%20%5Cfrac%7B79%7D%7B190%7D%20%3D%20%5Cfrac%7B111%7D%7B190%7D%5C%5C%5C%5C)
The probability that the two sweets will not be the same type of sweet =
111 / 190