Relative extrema occur where the derivative is zero (at least for your polynomial function).
So taking the derivative we get
<span>20<span>x3</span>−3<span>x2</span>+6=0
</span><span>
This is a 3rd degree equation, now if we are working with complex numbers this equation is guaranteed to have 3 solutions by the fundamental theorem of algebra. But the number of real roots are 1 which can be found out by using Descartes' rule of signs. So the maximum number of relative extrema are 1.</span>
a. use the month for x
Income
point (1,1500) (2 3500)
slope (y2-y1)/(x2-x1) =(3500-1500)/(2-1)=2000
y-y1=m(x-x1)
y-1500 = 2000(x-1)
y-1500=2000x-2000
y = 2000x-500
Expenses
point (1,21400) (2 18800)
slope (y2-y1)/(x2-x1) =(18800-21400)/(2-1)=-2600
y-y1=m(x-x1)
y-21400 = -2600(x-1)
y-21400=-2600x+2600
y = -2600x+24000
b 2000x-500=-2600x+24000
add 2600x to each side
4600x -500 = 24000
add 500 to each side
4600x = 24500
divide by 4600
x=5.326 months
Solve the system by graphing
{2x - 4y = -4 -4y = -2x-4 y = 1/2x +1 slope is 1/2 y intercept 1
{3x - y = 4 -y =-3x +4 y = 3x-4 slope is 3 y intercept is -4
this one you have to do cannot graph here the solution is x=2, y=2
Classify the system without graphing
{y = 12 - 5x
{x - 4y = -6
independent system
dependent system is the same line and has infinite solutions
inconsistent system has no solutions (parallel lines)
Answer:
d. 0.0948 ± 4.032(0.0279)
Step-by-step explanation:
A 99% confidence interval for the coefficient of promotional expenditures is, First, compute the t critical value then find confidence interval.
The t critical value for the 99% confidence interval is,
The sample size is small and two-tailed test. Look in the column headed es = 0.01 and the row headed in the t distribution table by using degree of freedom is here
for (n-2=5) degree of freedom and 99% confidence ; critical t =4.032
therefore 99% confidence interval for the slope =estimated slope -/+ t*Std error
= 0.094781123 -/+ 4.032* 0.027926367 = -0.017822 to 0.207384
