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Irina18 [472]
3 years ago
9

SOMEONE PLEASE ANSWER ASAP!! 55 POINTS!!

Mathematics
1 answer:
nadezda [96]3 years ago
4 0

Answer:

EG = 16 and FH =22

Step-by-step explanation:

We know that the diagonals of a parallelogram bisect each other

so 2a  = 3b+2

and 2a+3 = 6b-1

We know have a system of equations to solve

2a  = 3b+2

 2a+3 = 6b-1

Subtract 3 from each side

2a+3-3 = 6b-1-3

2a = 6b -4

Now we can set the 2 equations equal  ( 2a  = 3b+2  and 2a = 6b -4)

3b+2 = 6b-4

Subtract 3b from each side

3b-3b+2 = 6b-3b-4

2 = 3b-4

Add 4 to each side

2+4 = 3b-4+4

6 = 3b

Divide by 3

6/3 = 3b/3

2 =b

We want to find a

2a  = 3b+2

Substitute in b=2

2a = 3(2) + 2

2a = 6+2

2a =8

Divide by 2

2a/2 =8/2

a = 4

Now that we know a and b

EG = 2a + 3b+2

    = 2(4) + 3(2)+2

   = 8+6+2

   = 16

FH = 2a+3 + 6b-1

    = 2(4) +3 +6(2)-1

    = 8+3+12-1

   = 23-1

  = 22

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The volume of a cylinder is 252π cm3 and its height is 7 cm. What is the cylinder’s radius? A. 36 B. 80 C.16 D.6
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3 years ago
A ride-share company has a fee that includes a fixed cost and a cost that depends on both the time spent travelling, in minutes,
zlopas [31]

Answer:

the cost of Roy's ride is $23.05

Step-by-step explanation:

According to the Question,

Let, Cost of per minute charge is 'x' & Cost Of Per Kilometre charge is y .

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  • And, The Total cost of the Ride depends on both the time spent on travelling(in minutes), and the distance travelled(in kilometres) .

⇒ Judy's ride costs $16.75 . but the actual cost after deducting the fixed charge is 16.75-2.55 = $14.20, took 8 minutes & The distance travelled was 10 km. Thus, the equation for the journey is 8x+10y=14.20 ⇒ Equ. 1

⇒ Pat's ride costs $30.35 . but the actual cost after deducting the fixed charge is 30.35-2.55 = $27.80, took 20 minutes & The distance travelled was 18 km. Thus, the equation for the journey is 20x+18y=27.80 ⇒ Equ. 2

Now, on Solving Equation 1 & 2, We get

x=0.4(Cost of per minute charge) & y=1.1(Cost Of Per Kilometre charge)

Now, Roy's ride took 10 minutes & The distance travelled was 15 km . Thus, the cost of Roy's Ride is 10x+15y ⇔ 10×0.4 + 15×1.1 ⇔ $20.5

Hence, the total cost of Roy's ride is 20.5 + 2.55(fixed cost) = $23.05

8 0
3 years ago
Why can’t one of the names be PNM, or MPN for the plane? But MNP can? What’s the difference, and why?
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3 0
2 years ago
Let <img src="https://tex.z-dn.net/?f=%5Csf%20a%2Bb%2Ca-b%2Cab%2C%5Cdfrac%7Ba%7D%7Bb%7D" id="TexFormula1" title="\sf a+b,a-b,ab,
Black_prince [1.1K]

Answer:

  • 171/40 or 4 11/40

Step-by-step explanation:

<h3>AP given</h3>
  • a + b, a - b,  ab, a/b
<h3>To find</h3>
  • 6th term
<h3>Solution</h3>

Common difference

<u>Difference of first two</u>

  • d = (a -b) - (a + b) = -2b

<u>Difference of second two</u>

  • d= ab - (a - b)

<u>Difference of last two</u>

  • d = a/b - ab

<u>Now comparing d:</u>

  • -2b = ab - (a - b)
  • ab - a = - 3b
  • a(1 - b) = 3b
  • a = 3b/(1 - b)

and

  • a/b - ab = -2b
  • a(1/b - b) = -2b
  • a = 2b²/(b² - 1)

<u>Eliminating a:</u>

  • 2b²/(b² - 1) = 3b/(1 - b)
  • 2b/(b+1) = -3
  • 2b = -3b - 3
  • 5b = - 3
  • b = -3/5

<u>Finding a:</u>

  • a = 3b/(1 - b) =
  • 3*(-3/5) *1/(1 - (-3/5)) =
  • -9/5*5/8 =
  • -9/8

<u>So the first term is:</u>

  • a + b = -3/5 - 9/8 = -24/40 - 45/40 = - 69/40

<u>Common difference:</u>

  • d = -2b = -2(-3/5) = 6/5

<u>The 6th term:</u>

  • a₆ = a₁ + 5d =
  • -69/40 + 5*6/5 =
  • -69/40 + 240/40 =
  • 171/40 = 4 11/40
8 0
3 years ago
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