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Drupady [299]
3 years ago
10

Answer this and I’ll make you Brainly

Mathematics
2 answers:
FrozenT [24]3 years ago
8 0
The answer is f(x) = (x/4) - 3

4/4=1-3=-2
True [87]3 years ago
3 0

Answer:

A. f(x)=(x/4)-3

Step-by-step explanation:

Function is f(x)=(x/4)-3,

If x=0, then f(0)=0-3=-3

If x=4, then f(4)=(4/4)-3=1-3=-2

If x=-8, then f(-8)=(-8/2)-3=-2-3=-5

You might be interested in
Find the length of side y
Serggg [28]

Answer:

\large\boxed{y=76.3359\ cm\approx76.3\ cm}

Step-by-step explanation:

Use cosine:

cosine=\dfrac{adjacent}{hypotenuse}

We have

adjacent=73\ cm\\hypotenuse=y

and the angle 17°.

\cos17^o\approx0.9563

Substitute:

\dfrac{73}{y}=0.9563             <em>convert the decimal to the fraction</em>

\dfrac{73}{y}=\dfrac{9563}{10000}          <em>cross multiply</em>

9563y=730000           <em>divide both sides by 9563</em>

y=\dfrac{730000}{9563}

y\approx76.3359

8 0
3 years ago
What is the value of x? x = <br><br> What is the perimeter of ΔABC?
Kryger [21]

Answer: find the third value when two values

The perimeter of ΔABC is 13 cm

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Solve log (x + 1) = –x2 + 10 by graphing. Which equations should be graphed?
GarryVolchara [31]
Y2 = log (x+1) is the answer
4 0
3 years ago
Read 2 more answers
Find the unknown length x in the right triangle, to the nearest tenth.<br> 16<br> 21
PIT_PIT [208]

Answer:

16 rounded to the nearest 10 is 20

21 rounded to the nearest 10 is 20

so I don't really know but I guess you should put the x as 20 for sure UwU

3 0
3 years ago
Urgent!
boyakko [2]

Step-by-step explanation:

18.

the last one.

-4.9t² + 24.5t + 117.6 = 0

the ball starts at 117.6 meters height. then, during the first seconds the thrust upwards is adding height, until finally, with more and more seconds passing, gravity will win with a vengeance and pulls the ball down faster and faster than any other force in any other direction.

19.

the general solution for a quadratic equation

y = ax² + bx + c

is

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case

x = t

a = -4.9

b = 24.5

c = 117.6

t = (-24.5 ± sqrt(600.25 - -4×4.9×117.6))/-9.8 =

= (-24.5 ± sqrt(600.25 + 2304.96))/-9.8 =

= (-24.5 ± sqrt(2905.21))/-9.8 = (-24.5 ± 53.9)/-9.8

t1 = (-24.5 + 53.9)/-9.8 = -3

t2 = (-24.5 - 53.9)/-9.8 = 8

a negative time does not make any sense, so the real solution is : the ball reached the ground after 8 seconds.

20.

now the equation is

-4.9t² + 24.5t + 117.6 = 49

but this is quickly transformed again into a "= 0" equation :

-4.9t² + 24.5t + 68.6 = 0

t = (-24.5 ± sqrt(600.25 - -4×4.9×68.6))/-9.8 =

= (-24.5 ± sqrt(600.25 + 1344.56))/-9.8 =

= (-24.5 ± sqrt(1944.81))/-9.8 = (-24.5 ± 44.1)/-9.8

t1 = (-24.5 + 44.1)/-9.8 = -2

t2 = (-24.5 - 44.1)/-9.8 = 7

again, negative time does not make sense.

the ball will be at 49 m height after 7 seconds.

5 0
2 years ago
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