1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Damm [24]
3 years ago
7

What are the odds of a coin landing on heads 10 times in a row?

Mathematics
2 answers:
Margarita [4]3 years ago
6 0
Odds of coin landing on heads 1 time are 1/2(what can be written as 2^-1)
Odds of coin landing on heads 10 times are (1/2)^10 = 2^-1^10=2^-10
svetlana [45]3 years ago
4 0
\text { P(head) =} \dfrac{1}{2}

\text { P(10 heads in a row) =}  \bigg( \dfrac{1}{2}\bigg )^{10} = \dfrac{1}{1024}


You might be interested in
Sofia is buying new skis. She finds that the average price of skis is $500 but the actual price could differ from the average as
prisoha [69]
The equation that best represent the actual prices of the skis is,
                    I x - 500 I ≥ 250
Solving the absolute value equation,
                       x ≤ 750 and x ≥ 250 
Thus, the prices of the skis ranges from 250 to 750. 
5 0
4 years ago
If dinner costs 31 British pounds, then how much is that in U.S. Dollars?
kaheart [24]

Answer:

If dinner cost 31 British pounds than $38.78 would be the cost in U.S. dollars.

I hope this helps!

8 0
3 years ago
Read 2 more answers
What is the approximate value for the modal daily sales?
Aleksandr [31]

Answer:

Step-by-step explanation:

Hello!

<em>The table shows the daily sales (in $1000) of shopping mall for some randomly selected  days </em>

<em>Sales 1.1-1.5 1.6-2.0 2.1-2.5 2.6-3.0 3.1-3.5 3.6-4.0 4.1-4.5 </em>

<em>Days 18 27 31 40 56 55 23 </em>

<em>Use it to answer questions 13 and 14. </em>

<em>13. What is the approximate value for the modal daily sales? </em>

To determine the Mode of a data set arranged in a frequency table you have to identify the modal interval first, this is, the class interval in which the Mode is included. Remember, the Mode is the value with most observed frequency, so logically, the modal interval will be the one that has more absolute frequency. (in this example it will be the sales values that were observed for most days)

The modal interval is [3.1-3.5]

Now using the following formula you can calculate the Mode:

Md= Li + c[\frac{(f_{max}-f_{prev})}{(f_{max}-f_{prev})(f_{max}-f_{post})} ]

Li= Lower limit of the modal interval.

c= amplitude of modal interval.

fmax: absolute frequency of modal interval.

fprev: absolute frequency of the previous interval to the modal interval.

fpost: absolute frequency of the posterior interval to the modal interval.

Md= 3,100 + 400[\frac{(56-40)}{(56-40)+(56-55)} ]= 3,476.47

<em>A. $3,129.41 B. $2,629.41 C. $3,079.41 D. $3,123.53 </em>

Of all options the closest one to the estimated mode is A.

<em>14. The approximate median daily sales is … </em>

To calculate the median you have to identify its position first:

For even samples: PosMe= n/2= 250/2= 125

Now, by looking at the cumulative absolute frequencies of the intervals you identify which one contains the observation 125.

F(1)= 18

F(2)= 18+27= 45

F(3)= 45 + 31= 76

F(4)= 76 + 40= 116

F(5)= 116 + 56= 172 ⇒ The 125th observation is in the fifth interval [3.1-3.5]

Me= Li + c[\frac{PosMe-F_{i-1}}{f_i} ]

Li: Lower limit of the median interval.

c: Amplitude of the interval

PosMe: position of the median

F(i-1)= accumulated absolute frequency until the previous interval

fi= simple absolute frequency of the median interval.

Me= 3,100+400[\frac{125-116}{56} ]= 3164.29

<em>A. $3,130.36 B. $2,680.36 C. $3,180.36 D. $2,664</em>

Of all options the closest one to the estimated mode is C.

5 0
3 years ago
Simplify the algebraic question 3(2x+5)-4
saul85 [17]
6x+15-4
6x+11
Hope this helps
6 0
3 years ago
The wildlife department has been feeding a special food to rainbow trout fingerlings in a pond. based on a large number of obser
Liono4ka [1.6K]
The normal distribution curve for the problem is shown below

We need to standardise the value X=405.5 by using the formula

z-score= \frac{X-Mean}{Standard Deviation}
z-score= \frac{405.5-402.7}{8.8} =0.32

We now need to find the probability of z=0.32 by reading the z-table

Note that z-table would give the reading to the left of z-score, so if your aim is to work out the area to the right of a z-score, then you'd need to do:

P(Z\ \textgreater \ z)=1 - P(Z\ \textless \ z)

from  the z-table, the reading P(Z\ \textless \ 0.32) gives 0.6255

hence, 
P(Z\ \textgreater \ 0.32)=1-0.6255=0.3475

The probability that the mean weight for a sample of 40 trout exceeds 405.5 gram is 0.3475 = 34.75%

7 0
3 years ago
Other questions:
  • A golf ball is dropped from a height of 30 ft to the pavement, and the rebound is one fourth the distance it drops. if after eac
    10·1 answer
  • Would this be correct? I have to write it as a single power.
    5·1 answer
  • -5(3x – 1) – 20 = 7(5) – 5
    11·1 answer
  • Determine the exact value of sin 150 degrees
    13·1 answer
  • Find the domain of the following graph:
    8·1 answer
  • True or False ? Can you represent the distance of an object underground using negative numbers?
    5·1 answer
  • Least to greatest 0.7 0.25 0.6 0.28
    14·2 answers
  • Answer please helpppp!!!
    5·2 answers
  • I need help please!!! thank you so much to the person who is going to help me.
    8·2 answers
  • Prove that:
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!