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3 years ago

What are the odds of a coin landing on heads 10 times in a row?

2 answers:

6 0

Odds of coin landing on heads 1 time are 1/2(what can be written as 2^-1)
Odds of coin landing on heads 10 times are (1/2)^10 = 2^-1^10=2^-10

svetlana [45]3 years ago

4 0

$\text { P(head) =} \dfrac{1}{2}$

$\text { P(10 heads in a row) =} \bigg( \dfrac{1}{2}\bigg )^{10} = \dfrac{1}{1024}$

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An artist builds a sculpture out of metal and wood that weighs 14.9 kilograms. 3/4 of this weight is metal and the rest is wood.

Troyanec [42]

Answer:

Given is a sculpture that is built up of metal and wood, and the weight of this sculpture is 14.9 kilograms.

It says that three-fourth of the total weight is metal and says to find the weight of wooden part.

We can find the weight of metal part and then subtract it from the total weight to calculate the answer.

Total weight = 14.9 kilograms.

Metal part = three-fourth of total weight =

Wooden part = 14.9 - 11.175 = 3.725 kilograms.

Hence, the wooden part is 3.725 kilograms.

Step-by-step explanation:

8 0

3 years ago

Combine the like terms to create an equivalent expression: 2s+(-4s)

Ira Lisetskai [31]

Answer:

-2s

Step-by-step explanation:

2s+(-4s)

2s-4s

-2s

Hope this helps ;) ❤❤❤

5 0

3 years ago

Read 2 more answers

Solve these equation 4(3-x)=(1-2x)

serg [7]

To attempt this algebraic equation we will be multiplying 4 to (3 - x) bracket so as to form the term on L.H.S.

$:\implies\tt{4(3 - x) = (1 - 2x)}$

$:\implies\tt{(12 - 4x) = (1 - 2x)}$

$:\implies\tt{12 - 4x = 1 - 2x}$

Combining like terms, we get,

$:\implies\tt{12 - 1 = - 2x + 4x}$

$:\implies\tt{11 = 2x}$

$:\implies\tt{2x = 11}$

$:\implies\tt{x = \frac{11}{2} }$

$:\implies\tt{x = 5.5}$

The value of x is 5.5

8 0

2 years ago

70 days=?Weeks Hey guess if u help me I will help u thx

hjlf

The answer is 10 weeks

6 0

3 years ago

Read 2 more answers

A right rectangular prism has edges of 2 1/4 in, 1 1/2 in and 1 1/2 in. How many cubes with lengths of 1/4 in would be needed to

Zielflug [23.3K]

The volume of a rectangular prism is (length) x (width) x (height).

The volume of the big one is (2.25) x (1.5) x (1.5) = 5.0625 cubic inches.

The volume of the little one is (0.25)x(0.25)x(0.25)= 0.015625 cubic inch

The number of little ones needed to fill the big one is

 (Volume of the big one) divided by (volume of the little one) .

 5.0625 / 0.015625 = 324 tiny cubies

=================================================

Doing it with fractions instead of decimals:

The volume of a rectangular prism is (length) x (width) x (height).
Dimensions of the big one are:

 2-1/4 = 9/4
 1-1/2 = 3/2
 1-1/2 = 3/2

 Volume = (9/4) x (3/2) x (3/2) =

 (9 x 3 x 3) / (4 x 2 x 2) =

 81 / 16 cubic inches.

As a mixed number: 81/16 = 5-1/16 cubic inches

Volume of the tiny cubie = (1/4) x (1/4) x (1/4) = 1/64 cubic inch.

The number of little ones needed to fill the big one is

 (Volume of the big one) divided by (volume of the little one) .

 (81/16) divided by (1/64) =

 (81/16) times (64/1) =

 5,184/16 = 324 tiny cubies.

5 0

3 years ago