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icang [17]
3 years ago
5

The top of a table is in the shape of a trapezoid. It has a height 1.5 feet and the two parallel bases measure 3 feet and 5 feet

. What is the area of the top of the table?
A = 1
2
(b1 + b2)h

A = 1
2
(3 + 5)(1.5)

A = 1
2
(8)(1.5)

The area of the tabletop is:
2.3 feet2
6 feet2
12 feet2
22.5 feet2
Mathematics
1 answer:
Ksju [112]3 years ago
7 0

Answer: 6 feet 2

Step-by-step explanation:

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Cost-volume profit analysis reclined company is planning to produce and sell 11,250 units of its only product at a unit price of
ollegr [7]

Answer:

The contribution margin it's determined by the total amount of Gross Profit divided by the total value of sales.

Profit = $405,000

Sales = 11,250×106 =$1,192,500

Therefore contribution margin ratio = ($405,000/$1,192,500) = 0.34

The Break Even point is given thus;

Fixed cost = 25 × 11250 =$281,250

Break-even point = Fixed costs ÷ contribution ratio

= $281,250/0.34 = $827,205.88

5 0
3 years ago
In an endurance race, Rachel ran
Reil [10]

Answer:

31\frac{1}{5}\ miles

Step-by-step explanation:

we know that

The speed is equal to divide the distance by the time

so

The distance is equal to multiply the speed by the time

we have

speed=9\frac{3}{5}\ \frac{miles}{hour}

time=3\frac{1}{4}\ hours

distance=(9\frac{3}{5})(3\frac{1}{4})

Convert mixed number to an improper fraction

9\frac{3}{5}=9+\frac{3}{5}=\frac{9*5+3}{5}=\frac{48}{5}

3\frac{1}{4}=3+\frac{1}{4}=\frac{3*4+1}{4}=\frac{13}{4}

substitute

distance=(\frac{48}{5})(\frac{13}{4})=\frac{624}{20}=31,2\ miles

Convert to mixed number

31.2\ mi=31+0.2=31+\frac{1}{5}=31\frac{1}{5}\ miles

3 0
3 years ago
What is the to this answer
Rzqust [24]
The answer is is c 42.9%
4 0
3 years ago
Please help!!!!! For the data set shown by the table
Rom4ik [11]
B) lograrithmic
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8 0
4 years ago
Find the slope of each line and then determine if the lines are parallel, perpendicular or neither. If a value is not an integer
Aleonysh [2.5K]

As given by the question

There are given that the point of two-line

\begin{gathered} (1,\text{ 7) and (5, 5)} \\ (-1,\text{ -3) and (1, 1)} \end{gathered}

Now,

From the condition of a parallel and perpendicular line

If the slopes are equal then the lines are parallel

If the slopes are negative reciprocal then the lines are perpendicular

If the slopes are neither of the above are true then lines are neither

Then,

First, find the slope of both of line

So,

For first-line, from the formula of slope

\begin{gathered} m_1=\frac{y_2-y_1}{x_2-x_1} \\ m_1=\frac{5_{}-7_{}}{5_{}-1_{}} \\ m_1=-\frac{2}{4} \\ m_1=-\frac{1}{2} \end{gathered}

Now,

For second-line,

\begin{gathered} m_1=\frac{y_2-y_1}{x_2-x_1} \\ m_1=\frac{1_{}-(-3)_{}}{1-(-1)_{}} \\ m_1=\frac{4}{2} \\ m_1=2 \end{gathered}

The given result of the slope is negative reciprocal because

\begin{gathered} -\frac{1}{2}=-(-\frac{2}{1}) \\ -\frac{1}{2}=2 \end{gathered}

Hence, the slope of line1 is -1/2, and slope of line2 is 2 and the lines are perpendicular.

5 0
1 year ago
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