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Andrews [41]
3 years ago
13

Find the measurement of the indicated angle to the nearest degree

Mathematics
1 answer:
MaRussiya [10]3 years ago
4 0

Answer:

42

Step-by-step explanation:

This time, you'll be doing SOH.

sin (x) = 39/59=0.66

then do sin^-1 (0.66)

x = 42 degrees (think this is correct I hope)

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A picture is 10 inches by 14inches. The frame measures 2 inches longer and wider than the painting. What is the area of the fram
kow [346]

Answer:

52

Step-by-step explanation:

so first you do 10x14=140

next you have to do 12x16=192

then u have to do 192-140=52in squared

4 0
2 years ago
Solve the given equation. (Enter your answers as a comma-separated list. Let k be any integer. Round terms to three decimal plac
vredina [299]
-1\le\sin\theta\le1\implies(\csc\theta\le-1)\cup(\csc\theta\ge1)

which means \csc\theta=0 has no solution, and we can omit that factor.

This leaves us with

2\cos\theta-1=0\implies\cos\theta=\dfrac12

which occurs for \theta=\pm\dfrac\pi3+2n\pi.
3 0
4 years ago
The value of the x- intercept for the graph of 4x-5y=40 is
andrew-mc [135]
4x - 5y = 40

4x = 40 + 5y
x = 10 + 5/4y 

The x intercept is 10. 




8 0
3 years ago
The bending of a bean varies directly as its mas. A beam is bent 20mm by a mass 0f 40kg. how much will the beam bend with a mass
Naddik [55]

Answer:

The beam will bend by 50 mm with a mass of 100kg?

Step-by-step explanation:

The first step in solving the problem of direct variation is setting up the relation mathematically.

We can do this as follows:

The bending of the beam varies directly as its mass.

20  \alpha  40kg

\alpha here is the symbol representing direct variation. To remove this and replace it with an equality sign, we have to introduce a constant of proportionality, k

20 = k \times 40

k = 20 /40 = 0.5

We can now use this to find the distance the beam will bend with a mass of 100kg?

This will be

Bending = 0.5 \times 100 =50mm

There fore, the beam will bend by 50 mm with a mass of 100kg?

6 0
4 years ago
Read 2 more answers
The diagram below represents a generic right triangle.
Oksi-84 [34.3K]
Bshould be the answer !
4 0
3 years ago
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