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Minchanka [31]
3 years ago
14

34. The researchers conducting the studies chose to use a

Chemistry
1 answer:
Zinaida [17]3 years ago
7 0

nonporous and impermeable, and therefore incapable of absorbing water.

Explanation:

The researchers made the choice because the plastic is non-porous and impermeable and therefore incapable of absorbing water.

One deterrent to this experiment would have been a material that absorbs water.

  • Porosity is the void spaces within a material.
  • Permeability is the inter-connectivity voids created by the pore spaces.
  • A porous and permeable material will absorb water.
  • A non-porous and non-permeable material will not absorb water.

Learn more:

Permeable brainly.com/question/1220097

#learnwithBrainly

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The equilibrium system described by this equation has reactant molecule(s) and product gas molecule(s).
Evgesh-ka [11]

For N2(g)+3h2(g) ←→ ​​​​​​​2nh3(g) The equilibrium system described by this equation has= 3  reactant molecule(s) and= 2  product gas molecule(s).

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When 2.714 g of AX (s) dissolves in 127.4 g of water in a coffee-cup calorimeter the temperature rises from 23.3 °C to 37.1 °C.
MakcuM [25]

Answer : The enthalpy change for the solution is 166.34 kJ/mol

Explanation :

First we have to calculate the enthalpy change of the reaction.

Formula used :

\Delta H=mC\Delta T\\\\\Delta H=mC(T_2-T_1)

where,

\Delta H = change in enthalpy = ?

C = heat capacity of water = 4.18J/g.K

m = total mass of sample = 2.174 + 127.4 = 129.6 g

T_1 = initial temperature = 23^oC=273+23=296K

T_2 = final temperature = 37.1^oC=273+37.1=310.1K

Now put all the given values in the above expression, we get:

\Delta H=mC(T_2-T_1)

\Delta H=129.6g\times 4.18J/g.K\times (310.1-296)K=7638.36J

Now we have to calculate the moles of AX added to water.

\text{ Moles of }AX=\frac{\text{ Mass of }AX}{\text{ Molar mass of }AX}=\frac{2.714g}{59.1097g/mole}=0.04592moles

Now we have to calculate the enthalpy change for the solution.

As, 0.04592 moles releases heat = 7638.36 J

So, 1 moles releases heat = \frac{7638.36}{0.04592}=166340.59J=166.34kJ

Therefore, the enthalpy change for the solution is 166.34 kJ/mol

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3 years ago
Avagadros Law..<br>Definition please..​
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Answer:

"Avogadro's law is an experimental gas law relating the volume of a gas to the amount of substance of gas present. The law is a specific case of the ideal gas law. A modern statement is: Avogadro's law states that "equal volumes of all gases, at the same temperature and pressure, have the same number of molecules."

8 0
3 years ago
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The rate constants of some reactions double with every 10-degree rise in temperature. Assume that a reaction takes place at 295
LUCKY_DIMON [66]

Answer : The activation energy for the reaction is, 51.9 kJ

Explanation :

According to the Arrhenius equation,

K=A\times e^{\frac{-Ea}{RT}}

or,

\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

K_1 = rate constant at 295 K

K_2 = rate constant at 305 K = 2K_1

Ea = activation energy for the reaction = ?

R = gas constant = 8.314 J/mole.K

T_1 = initial temperature = 295 K

T_2 = final temperature = 305 K

Now put all the given values in this formula, we get:

\log (\frac{2K_1}{K_1})=\frac{Ea}{2.303\times 8.314J/mole.K}[\frac{1}{295K}-\frac{1}{305K}]

Ea=51879.96J=51.9kJ

Therefore, the activation energy for the reaction is, 51.9 kJ

8 0
4 years ago
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