Explanation:
Not only did outermost electron determine the valence electron, but also <em>periodic</em><em> </em><em>table</em><em>.</em><em> </em>whatever group they fall into in periodic table each valence electrons present in a particular atom e.g K and Ca belong to group 1 and 2 respectively and k has 1 and Ca have 2 in each outermost electron
Answer:
Half life = 1 / k[Ao]
Explanation:
From:
1/ [A] = kt + 1/ [Ao]
Isolating t on its own, we have:
kt = 1 / [A] - 1 / [Ao]
t = 1 / [Ao] / k
Re-arranging we have:
t = 1 / k [Ao]
The t represents the t=half life of the second order reaction and the formula can be re-written as:
t1/2 = 1 / k [Ao]
This is so because second order reaction decreases at a much faster rate than zero and first order reactions and there slopes decreases to zero at a much faster rate.
Answer:
In the above reaction, sulfur dioxide and oxygen react together to form sulfur trioxide. This means that an increase in pressure would move the equilibrium to the right and result in more sulfur trioxide being formed. Pressure can only affect the position of equilibrium if there is a change in the total gas volume.
CaO ( calcium oxide) is a basic oxide.
Answer:
NO
Explanation:
Barium cannot ionically bond with Kalium. Kalium is the Latin name for potassium.
Both Barium and potassium are metals. Metals and Metals do not combine to form ionic compounds. Only metals and non-metals form this bond type.
- The reason for this is that ionic bond forms by the transfer of electrons from one specie to another that receives it.
- Barium is metal and would freely donate electrons to attain stability.
- Kalium is metal and shares similar property.
