The percentage of people accessing the internet from 61% in 2000 to 87% in 2012.
1 answer:
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Answer: A B
Group A 0.25 0.75
Group B 0.45 0.55
Step-by-step explanation:
Since we have given that
Number of people of A in Group A = 15
Number of people of B in Group A = 45
Number of people of A in Group B = 20
Number of people of B in Group B = 25
Total number of people in Group A = 15+45 = 60
Total number of people in Group B = 20+25 = 45
So, Relative frequencies will be given below:
Relative frequency of A in Group A is given by
Relative frequency of B in Group A is given by
Relative frequency of A in Group B is given by
Relative frequency of B in Group B is given by
Hence, A B
Group A 0.25 0.75
Group B 0.45 0.55
Answer:
0.003
Step-by-step explanation:
By formula we know that:
z (x) = (x - m) / [sd / sqrt (n)]
where x is the value we want to know (60,000), m is the mean (63500), sd is the standard deviation (6100) and n is the sample size (35).
Replacing we have:
z (60000) = (60000 - 63500) / [6100 / sqrt (35)]
z = -3.39
If we look in the normal distribution table (attached), we have that the probability is 0.0003.
