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Katena32 [7]
3 years ago
13

Number 4 has me stuck ​

Mathematics
2 answers:
bonufazy [111]3 years ago
5 0
(-5C^2)^3-(5c)^6
-125C^5 - 15625c^6
Rudiy273 years ago
5 0

Answer:

-15750

Step-by-step explanation:

-125c^6 - 15625c^6

-15750

B/c the variables cancel out

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PLEASEEEEEEEEEEEEEEEEEE URGENT
jeyben [28]

Option C:

f(x) = 5x + 7 is the function of the input-output table.

Solution:

Option A: f(x) = 6x + 9

Input x = 1 in the above equation.

f(1) = 6(1) + 9

    = 6 + 9

f(1) = 15

But the output is 12 in the table.

So, it is not the function of the table.

Option B: f(x) = 7x + 5

Input x = 1 in the above equation.

f(1) = 7(1) + 5

f(1) = 12

Input x = 5 in the above equation.

f(5) = 7(5) + 5

f(5) = 40

But the output is 32 in the table.

So, it is not the function of the table.

Option C: f(x) = 5x + 7

Input x = 1 in the above equation.

f(1) = 5(1) + 7

f(1) = 12

Input x = 5 in the above equation.

f(5) = 5(5) + 7

f(5) = 32

Input x = 10 in the above equation.

f(10) = 5(10) + 7

f(10) = 57

Input x = 5 in the above equation.

f(15) = 5(15) + 7

f(15) = 82

All outputs are correct for the given input.

Hence it is the function of the table.

Option D: f(x) = 12x + 1

Input x = 1 in the above equation.

f(1) = 12(1) + 1

f(1) = 12

Input x = 5 in the above equation.

f(5) = 12(5) + 1

f(5) = 61

But the output is 32 in the table.

So, it is not the function of the table.

Hence Option C is the correct answer.

f(x) = 5x + 7 is the function of the input-output table.

4 0
4 years ago
Determine the possible rational zeros of this polynomial function using the rational zeros theorem:
sleet_krkn [62]

Answer:

See answer below

Step-by-step explanation:

The possible zeroes are p/q where p is factors of the constant and q is factors of the coefficient of the largest degree.

This means possible zeroes are ±15/4, ±5/4, ±3/4, ±1/4, ±15/2, ±5/2, ±3/2, ±1/2, ±15, ±5, ±3, ±1.

3 0
3 years ago
Please help! Brainliest to correct
vivado [14]

Answer:

Step-by-step explanation:

x +3 I x⁴ + 0x³ - 6x² + 0x  -28 I x³ - 3x² + 3x - 9

         x⁴ + 3x³

       <u>-       -      </u>

                -3x³ - 6x²

                -3x³ - 9x²

               <u>  +      +     </u>

                        3x² + 0x

                       3x²  + 9x

                       <u> -       -       </u>

                                -9x  -28

                                -9x  - 27

                                <u> +      +    </u>

                                         -1

P(x) =(x +3)* (x³ - 3x² + 3x - 9) + (-1)

7 0
3 years ago
Can someone help me solve for x &amp; explain how they got it please?? i have a test tomorrow!!
Fudgin [204]

Answer:

36=x^2+5x

x^2+5x-36=0

(x+9)(x-4)

x= 4

x= -9

The Answer can be 4 or -9, see which option you have.

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Drag each number to the box on the right so it matches the value of the expression on the left. Each number may be used once, mo
Ymorist [56]

Answer:

-62024.48

Step-by-step explanation:

Given

[ 4 * ( 4 + 3 ) ] - 3 [ ( 7 - 5 ) \div 1 2 ] * 2 ( 5.4 + 3 ) * ( 6 - 2 ) [ 9 \div 3 + 6 ] * 3 ( 4 + 3.2 ) * [ ( 9 - 2 ) + 2.5]

Required

Solve

The question is poorly formatted; the only way to answer this is to place the result of each step in brackets until brackets cannot be used.

So, we have

[ 4 * ( 4 + 3 ) ] - 3 [ ( 7 - 5 ) \div 1 2 ] * 2 ( 5.4 + 3 ) * ( 6 - 2 ) [ 9 \div 3 + 6 ] * 3 ( 4 + 3.2 ) * [ ( 9 - 2 ) + 2.5 ]

Solve the expressions in the inner brackets

[ 4 * 7 ] - 3 [ 2  \div 1 2 ] * 2 ( 8.4  ) * ( 4 ) [ 9 \div 3 + 6 ] * 3 ( 7.2 ) * [ 7 + 2.5 ]

Solve all divisions

[ 4 * 7 ] - 3 * \frac{1}{6}  * 2 ( 8.4  ) * ( 4 ) [ 3 + 6 ] * 3 ( 7.2 ) * [ 7 + 2.5 ]

[28] - 0.5  * (16.8) * (4) [9] * (21.6) * [9.5]

[28] - 0.5  * (16.8) *  [36] * (21.6) * [9.5]

Multiply through

28- 62052.48

-62024.48

3 0
3 years ago
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