Answer:
I believe it's A.
Step-by-step explanation:
brainliest?
Answer: D
Step-by-step explanation:
![20 - 16 = \sqrt{3} x](https://tex.z-dn.net/?f=20%20-%2016%20%3D%20%20%5Csqrt%7B3%7D%20x)
![4 = \sqrt{3x}](https://tex.z-dn.net/?f=4%20%3D%20%20%5Csqrt%7B3x%7D%20)
take square on both sides to get rid of the square root.
![{4}^{2} = {( \sqrt{3x)} }^{2}](https://tex.z-dn.net/?f=%20%7B4%7D%5E%7B2%7D%20%20%3D%20%20%7B%28%20%5Csqrt%7B3x%29%7D%20%7D%5E%7B2%7D%20)
16 = 3x
x = 16/3
Answer:
Yes, you can use this inequality to find the numbers of cars required.
Step-by-step explanation:
12 + 3n > 28 where n = the number of cars required
3n > 28 -12
3n > 16
n > 5 1/3
Greater than 5 1/3 gives 6 cars.
Answer:
+ 18
Step-by-step explanation:
Substitute 5 for the y in the problem. 5y means 5 times y.
+ 5*5 - 7
+ 25 - 7 (combine 25-7)
+ 18
Answer:
Step-by-step explanation:
Let shall be considering the Cosine rule in this situation.
a^2 = b^2+c^2- 2bc.cosA
Where a = ?
b = 21km
c 45km
A = 131
a^2 = 21^2+45^2-2(21*45).cos131
a^2 = 441+2025-1890(-0.6560)
a^2 = 2466+1239.951
a^2 = 3705.951
a= 60.876km
Finding the bearing of the port from the ship.
We shall be considering the Sine rule
Sin A/a = Sin B/b
Where A = ?
a = 45km
B = 131°
b = 60.876km
Sin A/45 = sin131/60.876
SinA×60.876 = 45×sin131
SinA×60.876= 45×0.7547
SinA×60.876 = 33.961
SinA= 33.961/60.876
SinA = 0.5578
A = sin^-1 0.5578
A = 33.9°