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3 years ago

Solve for x and y x-y=11 2x+y=19

Mathematics

2 answers:

Ilia_Sergeevich [38]3 years ago

7 0

X=10 y=-1
U can use Photomath for questions like this

Charra [1.4K]3 years ago

6 0

Answer:

x = 10

y = -1

Step-by-step explanation:

System of equations

x - y = 11

2x + y = 19

What is x and y?

To solve this, we need to find a way we can substitute one equation into another. Let's try the first equation.

x - y = 11

Add y to both sides :

x = 11 + y

Now substitute x from the first equation into x in the second equation :

2(11 + y) + y = 19

Distribute :

22 + 2y + y = 19

Add like terms :

22 + 3y = 19

Get y alone :

Subtract 22 from both sides :

3y = -3

Divide 3 from both sides :

y = -1

Now that we have y, let's substitute it into the easier equation, which would be the first one.

x - (-1) = 11

x + 1 = 11

Subtract 1 from both sides :

x = 10

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Which of the following constants can be added to x2 - 3x to form a perfect square trinomail?

serious [3.7K]

The constant that can be added to $x^2$ - 3x to form a perfect square trinomial is $2\frac{1}{4}$

The given expression is

$x^2$ - 3x

To form a perfect square trinomial

$(a-b)^2 =a^2-2ab+b^2$

The given expression is

$x^2$ - 3x

first we have to add a constant term with it

$x^2$ - 3x + z

By comparing the given expression and the perfect square trinomial

$a^2 =x^2$

a = x

Similarly

-2ab = 3x

where know a =x

Then,

-2b = 3

b = -3/2

Similarly

$b^2 = z$

$(\frac{-3}{2})^2$ = z

9/4 = z

Convert the simple fraction to mixed fraction

9/4 = $2\frac{1}{4}$

Hence, the constant that can be added to $x^2$ - 3x to form a perfect square trinomial is $2\frac{1}{4}$

The complete question is :

Which of the following constants can be added to x2 - 3x to form a perfect square trinomial?

$1\frac{1}{2},2\frac{1}{4}$ and $4\frac{1}{2}$

Learn more about perfect square trinomial here

brainly.com/question/16615974

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago

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Sav [38]

Answer:

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Step-by-step explanation:

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