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xz_007 [3.2K]
4 years ago
11

A rectangular swimming pool measures 30 meters by 50 meters. Tope swims back and forth the complete length of the pool parallel

to the long side of the pool. She swims at a constant speed of 50 meters per minute. Meanwhile, her sister Tomi walks clockwise along the edges of the pool at a constant positive speed in such a way that they meet every time Tope reaches her starting point at the shorter side of the pool. What is Tomi's slowest possible walking speed, in meters per minute?
Mathematics
1 answer:
nikklg [1K]4 years ago
7 0

Answer:

Tomi's slowest possible walking speed is 80 meters per minute

Step-by-step explanation:

Tope swims at a speed of 50 meters per minute

Distance back and forth the long side of the pool is 50+50 meters = 100 meters

Time required to complete one round (back and forth) is 100 / 50 = 2 minutes

Perimeter of the pool is 50+50+30+30 = 160 meters

To walk around the perimeter and meet Tope at the starting point, Tomi has to walk 160 meters in 2 minutes

Tomi’s speed = 160 meters / 2 minutes or 160 / 2 = 80 meters per minute

Tomi's slowest possible speed should be 80 meters per minute

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What is the solution to this system of equations y=x+6 and y=-.5x+3
juin [17]

Answer:

x=-6, y=0

Step-by-step explanation:

it's impossible to fully solve an equation where 2 variables are unknown. So we have to make it equal to 1 set. to do this, we have to think logically.

if y=x+6, then that means wherever it says y, we can put x+6. because x+6=x+6, right? so we plug x+6 into the second equation and get.

x+6=0.5x+3

to solve for x we subtract 6 from one side and 0.5 from the other and get

0.5x=-3

then we multiply both sides by 2 to make be a whole number

x=-6

now we just plug this into either equation. because the first one is easier, we can just set it up as

y=(-6)+6

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3 years ago
What is the radius of the circle?
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Answer:

3 11/12 in.

Step-by-step explanation:

The radius is simply half of the diameter.

7 5/6  divide by 2 =  3 11/12

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3 years ago
Given sinx=3/5 and x is in quadrant 2, what is the value of tan(x/2)
xxMikexx [17]
X is in the second quadrant means that x/2 is in the first quadrant.


Consider the right triangle drawn in the figure. Let tan(x/2)=a.

Then, let the length of the opposite side to x/2 be a, the adjacent side be 1 and the hypotenuse be square root of a squared +1, as shown in the figure.

sin(x/2)=|opp side|/ |hypotenuse| =  \frac{a}{ \sqrt{ a^{2}+1 } }

cos (x/2) = |adj side|/ |hypotenuse| =  \frac{1}{ \sqrt{ a^{2}+1 } }


from the famous identity: sin(2a)=2sin(a)cos(a), we have:

2sin(x/2)cos (x/2)=sin(x)

thus

2* \frac{a}{ \sqrt{ a^{2}+1 } }*\frac{1}{ \sqrt{ a^{2}+1 } }= \frac{3}{5}

2* \frac{a}{  a^{2}+1 }= \frac{3}{5}

10a=3 a^{2} +3

3 a^{2}-10a +3=0

(3a-1)(a-3)=0

thus a=1/3 or a=3


thus tan(x/2)=1/3 or tan(x/2)=3


Answer: {1/3, 3}

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The data represents correlation, not causation.

Since the data would form a perfectly straight line through the points, the correlation coefficient would be -1 for a perfect decreasing fit.
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This is not causation because there could be lurking variables we cannot see.
6 0
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