$\bf \cfrac{a}{b}\div \cfrac{c}{d}\implies \cfrac{a}{b}\cdot \cfrac{ d}{c}\qquad therefore \qquad \cfrac{3}{5}\div \cfrac{3}{15}\implies \cfrac{3}{5}\cdot \cfrac{15}{3}\implies \cfrac{3}{3}\cdot \cfrac{15}{5}\implies 3$

7 0

3 years ago

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A sanitary landfill has available space of 16.2 ha at an average depth of 10 m. Seven hundred sixty-five (765) cubic meters of s

AfilCa [17]

Answer:

16.3 years

Step-by-step explanation:

1 ha = 10,000 m^2

The total capacity of the landfill is:

$C = 16.2*10,000*10 = 1,620,000\ m^3$

If waste is compacted to twice its delivered density, its volume is half of the delivered volume. Assuming that a year has 52 weeks, the volume of compacted solid waste dumped per year is:

$V=52*(5*0.5*765)\\V=99,450\ m^3$

The expected life of the landfill is given by its capacity divided by the yearly volume:

$L=\frac{C}{V}=\frac{1,620,000}{99,450} \\L=16,3\ years$

The landfill has an expected life of 16.3 years.

6 0

3 years ago