Volume of a cone, V = πr^2h/3
r = Sqrt 3V/πh = Sqrt [(58.9*3)/(3.14*9)] = 2.5 cm, minimum
Surface area, A = πr [r+ Sqrt (h^2+r^2)] = 3.14*2.5*[2.5+ Sqrt (9^2+2.5^2)] = 92.95 cm^2
Therefore, minimum amount of paper required is 92.95 cm^2
Volume of the cube is 1000 cm³
Step-by-step explanation:
- Step 1: Find the volume of the cube.
Side of the cube = 10 cm
⇒ Volume of the cube =(side)³ = 10³ = 1000 cm³
The answer would be D
multiply -2 and (-4m-8) to get 8m+16
then subtract -2m to get 6m+16
Looking at the graph you can see that the domain of the function is:
[0, 3.85]
To find the range of the function, we must follow the following steps:
Step 1)
Evaluate for t = 0
h (0) = - 4.87 (0) ^ 2 + 18.75 (0)
h (0) = 0
Step 2)
find the maximum of the function:
h (t) = - 4.87t ^ 2 + 18.75t
h '(t) = - 9.74 * t + 18.75
-9.74 * t + 18.75 = 0
t = 18.75 / 9.74
t = 1.925051335
We evaluate the function at its maximum point:
h (1.925051335) = - 4.87 * (1.925051335) ^ 2 + 18.75 * (1.925051335)
h (1.93) = 18.05
The range of the function is:
[0, 18.05]
Answer:
Domain: [0, 3.85]
Range: [0, 18.05]
option 1
Answer:
f(-3) = 15
Step-by-step explanation:
f(x)= 2x^2 - 3
Plug in x = -3 into the function
f(-3) = 2(-3)^2 - 3
f(-3) = 18 - 3
f(-3) = 15
