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3 years ago

Explain how to get the variable alone in each equation. 84 + c = 11 y / 6 = 7

Mathematics

2 answers:

Alenkasestr [34]3 years ago

5 0

1. Subtract 84 from both sides
c = -73

2. Multiply both sides by 6
y = 42

Lady bird [3.3K]3 years ago

4 0

In the first one you would subtract 84 from both sides.

In the second one you would multiply both sides by 6.

Have a nice day.

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Can someone help please ? Thanks I’m advance

Pani-rosa [81]

Answer:

f(-3) = 16

Step-by-step explanation:

Given:

f(x) = 2x² + x + 1

Required:

f(-3)

Solution:

Substitute x = -3 into f(x) = 2x² + x + 1

f(-3) = 2(-3)² + (-3) + 1

f(-3) = 2*9 - 3 + 1

f(-3) = 18 - 3 + 1

f(-3) = 16

6 0

3 years ago

A group of four boys (Alex, Bryan, Chris, and David) and five girls (Megan, Nancy, Olivia, Pauline, and Rebecc?

aliina [53]

Answer:

a) P = 362880 ways

b) P = 2880 ways

Step-by-step explanation:

a) We have four boys and five girls, they are going to sit together in a row of 9 theater seats, without restrictions

We have a permutation of 9 elements

P = 9!

P = 9*8*7*6*5*4*3*2*1

P = 362880 ways

b) Boys must seat together, we have two groups of people

4 boys they can seat in 4! different ways

P₁ = 4!

P₁ = 4*3*2*1

P₁ = 24

And girls can seat in 5! dfferent ways

P₂ = 5!

P₂ = 5*4*3*2*1

P₂ = 120

To get total ways in the above mentioned condition, we have to multiply P₁*P₂

P = 24*120

P = 2880 ways

4 0

3 years ago

If the period of a sine function is the number of units before the cycle begins to repeat, why would the period of the regressio

Jlenok [28]

Answer:

This means that after going around the unit circle once (2π radians), both functions repeat. So the period of both sine and cosine is 2π . Hence, we can find the whole number line wrapped around the unit circle.

Step-by-step explanation:

5 0

3 years ago

50 POINTS!!! In rectangle ABCD, AB = 6 cm, BC = 8 cm, and DE = DF. The area of triangle DEF is one-fourth the area of rectangle

aalyn [17]

Answer:

$EF=4\sqrt{3}$

Step-by-step explanation:

In rectangle ABCD, AB = 6, BC = 8, and DE = DF.

ΔDEF is one-fourth the area of rectangle ABCD.

We want to determine the length of EF.

First, we can find the area of the rectangle. Since the length AB and width BC measures 6 by 8, the area of the rectangle is:

$A_{\text{rect}}=8(6)=48\text{ cm}^2$

The area of the triangle is 1/4 of this. Therefore:

$\displaystyle A_{\text{tri}}=\frac{1}{4}(48)=12\text{ cm}^2$

The area of a triangle is half of its base times its height. The base and height of the triangle is DE and DF. Therefore:

$\displaystyle 12=\frac{1}{2}(DE)(DF)$

Since DE = DF:

$24=DF^2$

Thus:

$DF=\sqrt{24}=\sqrt{4\cdot 6}=2\sqrt{6}=DE$

Since ABCD is a rectangle, ∠D is a right angle. Then by the Pythagorean Theorem:

$(DE)^2+(DF)^2=(EF)^2$

Therefore:

$(2\sqrt6)^2+(2\sqrt6)^2=EF^2$

Square:

$24+24=EF^2$

Add:

$EF^2=48$

And finally, we can take the square root of both sides:

$EF=\sqrt{48}=\sqrt{16\cdot 3}=4\sqrt{3}$

6 0

3 years ago

Read 2 more answers

A+b/a-b=5/3 what are the following ratios? 3a:2b

Papessa [141]

Answer:

3 a : 2 b = 6 : 1

Step-by-step explanation:

$\frac{a + b}{a - b}$ = $\frac{5}{3}$

3 ( a + b) = 5 ( a - b)

3 a + 3 b = 5 a - 5 b

5 b + 3 b = 5 a - 3 a

8 b = 2 a

2 a = 8 b

a = 4 b

3 a = 3 × 4 b

3 a = 12 b

3 a: 2 b = 12 b : 2 b

3 a : 2 b = 6 : 1

7 0

3 years ago

Read 2 more answers