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worty [1.4K]
3 years ago
7

Auditoriums are often designed so that are fewer seats per row for rows closer to the stage. Suppose you are sitting in row 18 i

n an auditorium and notice that there are 73 seats in your row. It appears the row in front of you has 70 seats and the row behind you has 76 seats. Suppose this pattern continues throughout the auditorium.
a) How many seats are in the first row?

b) How many seats are in the 30th row?

c) Write an explicit formula for the sequence where a, is the number of seats in the nh row
Mathematics
1 answer:
zhannawk [14.2K]3 years ago
4 0

Answer:

(a) 22 (b) 109

Step-by-step explanation:

GIVEN: Auditoriums are often designed so that are fewer seats per row for rows closer to the stage. Suppose you are sitting in row 18 in an auditorium and notice that there are 73 seats in your row. It appears the row in front of you has 70 seats and the row behind you has 76 seats. Suppose this pattern continues throughout the auditorium.

TO FIND: a) How many seats are in the first row b) How many seats are in the 30th row?

SOLUTION:

total seats in row_{19}=76

total seats in row_{18} =73

total seats in row_{17}=70

as it clearly form an A.P. with d=76-73=3

(a)

let total seat in first row be a

as total seats in row_{18}=73

row_{18}=a+(n-1)d

73=a+17\times3

a=22

total seats in first row are 22

(b)

total seats in 30th be x

x=row_{1}+(30-1)3

x=22+29\times3

x=109

total seats in 30th row  are 109

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An airline estimates that 94% of people booked on their flights actually show up. If the airline books 77 people on the flight for which the maximum number is 75, what is the probability that the number of people who show up will exceed the capacity of the plane?

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---

P(76 <= x <= 77) = 1-P(0 <=x <= 75) = 1 - binomcdf(77,0.94,75) = 0.0504

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Cheers,

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Step-by-step explanation:


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