Write an equation for the ordered pairs (0,5) (1,0)

What is the distance between the points (21 , 13) and (3 , 13) in the coordinate plane?

Oxana [17]

Answer:

$\displaystyle d = 18$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Coordinates (x, y)

Algebra II

Distance Formula: $\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step-by-step explanation:

Step 1: Define

Identify

Point (21, 13)

Point (3, 13)

Step 2: Find distance d

Simply plug in the 2 coordinates into the distance formula to find distance d

Substitute in points [Distance Formula]: $\displaystyle d = \sqrt{(3-21)^2+(13-13)^2}$
[√Radical] (Parenthesis) Subtract: $\displaystyle d = \sqrt{(-18)^2+(0)^2}$
[√Radical] Evaluate exponents: $\displaystyle d = \sqrt{324+0}$
[√Radical] Add: $\displaystyle d = \sqrt{324}$
[√Radical] Evaluate: $\displaystyle d = 18$

5 0

3 years ago

Which term best describes the graph of y = -2X + 4

Alexxandr [17]

Answer:

Decreasing, negative slope

Step-by-step explanation:

Bc the slope is -2x in this equation therefore its a negative slope.

3 0

2 years ago

The graphs of functions f(x) and g(x) = f(x) + k are shown below:

Nataly [62]

Here's the info for f(x): We are going to find the slope of the line and then write the equation for the line using one of the given points. The coordinate points we are given are (0, 0) and (2, 4). Using the slope formula:
$m= \frac{y_{2} - y_{1} }{ x_{2}- x_{1} }$
gives us a slope equation of:
$m= \frac{4-0}{2-0}$ and the slope is 2. Using the point (0, 0) to write the equation of the line for f(x) looks like this in the slope-intercept form of the equation:
$y- y_{1} =m(x- x_{1})$ where m is the sloppe of 2 that we found and $y_{1}$ and $x_{1}$ are the coordinates of one of the points. It doesn't matter which one you choose; you will get the same answer whether you use (0, 0) or (2, 4): y-0=2(x-0) Distributing that 2 into the parenthesis and simplifying gives you the equation of y = 2x, or in our function notation, f(x) = 2x. Since f(x) is the first part of g(x), so far for g(x) we have that g(x) = 2x + k. Now we will do the same thing for g(x) that we did for f(x) as far as writing its equation down; we don't need to find the slope cuz the slope of g(x) is the function f(x). The equation for g(x), using the point (0, 2) (again, you could have used either point; I just picked (0, 2) cuz the other one has a decimal in it!): y - 2 = 2(x - 0). Distributing that 2 into the parenthesis gives you this: y - 2 = 2x - 0; y = 2x + 2. So 2 is your k value!

7 0

3 years ago

Read 2 more answers

Need help with math problem give 5 stars and brain thingy point

Nadusha1986 [10]

Answer:

There are 12 sections, out of the 12 sections the third section is marked. So that would be, 3/12 which simplifies to 1/4

5 0

2 years ago

Read 2 more answers

Need help with linear approximation

Dmitrij [34]

Consider a function f(x), the linear approximation L(x) of f(x) is given by

$L(x)=f(a)+(x-a)f'(a)$

Given the quantity: $\frac{1}{203}$

We approximate the quantity using the function $f(x)= \frac{1}{x}$ , where x = 203.

We choose a = 200, thus the linear approximation is given as follows:

$L(203)=f(200)+(203-200)f'(200) \\ \\ = \frac{1}{200} - \frac{3}{200^2} = \frac{200-3}{200^2} = \frac{197}{40,000} =0.004925$

5 0

3 years ago