Answer:
The orders of magnitude are numbers of the form:
10^n
where n can be any integer number.
So we can write something like:
"A is n orders of magnitude above B
Now we have the quantities:
Amjed cards = 223
Latif cards = 8741
We want to find how many times more trading cards does Latif have than Amjed.
Then we need to look at the quotient between the number of cards of Latif and Amjed.
8741/223 = 39.2
Now we need to approximate this to the nearest 10^n number.
(..., 0.1, 1, 10, 100, 1000, ...)
The nearest one to 39.2 is 10.
So we can say that Latif's collection is 10.
and 10 = 10^1
then n = 1
Then we can say that Latif's collection is one order of magnitude above Amjed's collection.
The answer is 16773.6 because you just find the 34.8 percent of 48,200
Please report this guy he always send this same link everytime
Answer:
The values of a and b are 1 and -8
Step-by-step explanation:
Let us solve the question by comparing the two sides.
∵ x² + 2x - 7 = (x + a)² + b
→ Let us solve the bracket on the right side
∵ (x + a)² = (x)(x) + 2(x)(a) + (a)(a)
∴ (x + a)² = x² + 2ax + a²
→ Substitute it in the right side above
∴ x² + 2x - 7 = x² + 2ax + a² + b
→ Compare the like terms on both sides (terms of x², terms of x
and numerical terms)
∵ The terms of x are 2x and 2ax
→ Equate them
∵ 2x = 2ax
→ Divide both sides by 2x
∴
= 
∴ 1 = a
∴ The value of a = 1
∵ The numerical terms are -7 and a² + b
→ Equate them
∵ -7 = a² + b
→ Substitute a by 1
∴ -7 = (1)² + b
∴ -7 = 1 + b
→ Subtract 1 from both sides
∵ -7 - 1 = 1 - 1 + b
∴ -8 = b
∴ The value of b = -8
∴ The values of a and b are 1 and -8