Hello, let's note A the matrix, we need to find such that A= I, where I is the identity matrix, so the determinant is 0, giving us the characteristic equation as
We just need to solve this equation using the discriminant.
And then the eigenvalues are.
To find the basis, we have to solve the system of equations.
Thank you
Step-by-step explanation:
<h2>1)3.25x + -1.5y = 1.25</h2>
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '1.5y' to each side of the equation.
3.25x + -1.5y + 1.5y = 1.25 + 1.5y
Combine like terms: -1.5y + 1.5y = 0.0
3.25x + 0.0 = 1.25 + 1.5y
3.25x = 1.25 + 1.5y
<h2>2)13x-6y=10</h2>
13x + -6y = 10
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '6y' to each side of the equation.
13x + -6y + 6y = 10 + 6y
Combine like terms: -6y + 6y = 0
13x + 0 = 10 + 6y
13x = 10 + 6y
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<u>IF </u><u>ANY </u><u>DOUBT </u><u>(</u><u>OR) </u><u>CLARIFICATION </u>
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<h2>
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For this case, we observe that the dispersion diagram has a behavior similar to a straight line.
we observe that as the values of x increase, the values of y decrease.
Therefore, the line is of negative slope.
Answer:
Linear
option C
<u>ANSWER</u>
is an example of literal equation.
<u>EXPLANATION</u>
A literal equation is an equation in which letters or variables are used to represent real values.
A literal equation consists of at least two letters or variables.
The first option consists of two variables but it is not an equation. It is just an expression.
The second option is not a literal equation because it consists of only one variable. This is just a linear equation in one variable. But a literal equation should have at least two variables or letters.
As for the third option, it does not even contain a variable or letter.
Answer:
Yes you are on the right track!
Step-by-step explanation: