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3 years ago

Please help with questions a, b and c!!

Mathematics

1 answer:

Makovka662 [10]3 years ago

4 0

A) y=1/2 + 5

B) y=-1/2 + 8

C) y=1/2 - 10

Slope = M = Gradient

y-intercept = y-value = on y-coordinate

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Loren is flying round trip from Dallas, Texas, to Minneapolis, Minnesota. The fare for her ticket is $308. Each airport charges

KonstantinChe [14]

Answer:

Step-by-step explanation:

the fare : 308

airport fee : 2 * 16 = 32 (because there is 2 airports)

tax on fare : 12

total is : 308 + 32 + 12 = $352 <==

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2 years ago

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N76 [4]

Answer:

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Step-by-step explanation:

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8 0

2 years ago

30 POINTS FOR ANSWER!!<br> 2 numbers sum 120 and product 400<br> INSTANT ANSWER NEEDED

OLga [1]

I think the problem is
2X+20=400
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4 0

3 years ago

3p - 2(p-4) = 7p + 6

Serggg [28]

For this case we must find the value of the variable "p" of the following equation:

$3p-2 (p-4) = 7p + 6$

We apply distributive property on the left side of the equation taking into account that $+*-=-$ and $- * - = +$ :

$3p-2p + 8 = 7p + 6$

We add similar terms:

$p + 8 = 7p + 6$

We subtract $7p$ from both sides of the equation:

$p-7p + 8 = 6\\-6p + 8 = 6$

We subtract 8 from both sides of the equation:

$-6p = 6-8\\-6p = -2$

We divide by -6 on both sides of the equation:

$p = \frac {-2} {- 6}\\p = \frac {1} {3}$

Answer:

$p = \frac {1} {3}$

5 0

3 years ago

Help please?

Alla [95]

$\bf \begin{array}{clclll}
3^{1001}&\qquad &4^{1002}\\
\uparrow &&\uparrow \\
a&&b
\end{array}\\\\
-----------------------------\\\\
(a+b)^2-(a-b)^2\implies (a^2+2ab+b^2)-(a^2-2ab+b^2)
\\\\\\
a^2+2ab+b^2-a^2+2ab-b^2\implies 2ab+2ab\implies 4ab
\\\\\\
now\qquad 4(3^{1001})(4^{1002})=k12^{1001}\qquad 
\begin{cases}
12^{1001}\\
(4\cdot 3)^{1001}\\
4^{1001}\cdot 3^{1001}
\end{cases}$

$\bf \\\\\\
4(3^{1001})(4^{1002})=k(4^{1001}\cdot 3^{1001})\implies \cfrac{4(3^{1001})(4^{1002})}{4^{1001}\cdot 3^{1001}}=k
\\\\\\
4\cdot \cfrac{3^{1001}}{3^{1001}}\cdot \cfrac{4^{1002}}{4^{1001}}=k\implies 4\cdot 4^{1002}4^{-1001}=k\impliedby 
\begin{array}{llll}
\textit{same base}\\
\textit{add the}\\
exponents
\end{array}
\\\\\\
4\cdot 4^{1002-1001}=k\implies 4\cdot 4^1=k\implies 16=k$

6 0

3 years ago